Question

我如何在这里避免hardcoding身份证？下面是我正在硬编码id 22的代码。

it "can find an Project that this user belongs to" do 
    project = Project.find( id: '22', authorization: @auth )        
    hashed_response = FactoryGirl.build(:project_json).marshal_dump.to_json
    expect(project.to_json).to eq(hashed_response);
end

以下是完整课程的代码。

require 'spec_helper'

describe Project do

  before(:all) do
    @project = FactoryGirl.create(:project, name: "123", description: "123");
    @user =  FactoryGirl.create(:user, email: "test@test.com", password: nil, code: nil);
    user = User.login(FactoryGirl.create(:user, email: "test@test.com", 
                               password: "123", code: 0));

      if user
        @auth = user['auth']        
      end
  end

  it "can create an Project" do    
    expect{Project.create(project: @acc, user: @user)}.to 
                      change{Project.all(authorization: @auth).size}.by (1);    
  end

  it "can find an Project that this user belongs to" do 
    project = Project.find( id: '22', authorization: @auth )        
    hashed_response = FactoryGirl.build(:project_json).marshal_dump.to_json
    expect(project.to_json).to eq(hashed_response);
  end

end

我正在查看一些教程http://everydayrails.com/2012/04/07/testing-series-rspec-controllers.html，但我不明白它们是如何传递的。

Answer 1

如果项目属于用户，则可以执行...

project = Project.find_by( user_id: @user.id , authorization: @auth )

如果用户可以属于某个项目，那么你就可以......

project = Project.find_by( id: @user.project_id, authorization: @auth )

Answer 2

项目ID是如何提供的？用表格？那么它将是params [:id]或params [:project_id]，但在测试中它将是@ project.id

我怎样才能避免在find方法中使用id的'hardcoding`？

2 个答案: