Question

我正在尝试学习“如何在django中运行独立脚本”。我使用的是python2.7和django == 1.4.3。我创建了一个非常基本的脚本，我试图运行但面对 导入错误。我不想创建管理命令，因为这只是临时的东西，我的重点是学习。

我的代码

import os
import sys
from cartridge.shop.models import HomepageUpselling


class HomepageUpsellingToBestsellers():
    """This class copy the HomepageUpselling data to BestSellers"""

    def homepageuselling_to_bestsellers(self):
        """ Data Copy """
        hu_obj = HomepageUpselling.objects.all()
        for hu_iterable in hu_obj:
            bs_obj, created = \
                BestSeller.objects.get_or_create(product=hu_iterable.product,
                                                 variation=hu_iterable.variation)
            print "BestSeller data copying %s" % bs_obj.id
        return


if __name__ == "__main__":
    os.environ.setdefault("DJANGO_SETTINGS_MODULE", "project_name.setttings")
    sys.path.append(os.path.dirname(os.path.dirname(os.path.abspath(__file__))))
    from django.core.management import execute_from_command_line
    hu_to_bs_obj = HomepageUpsellingToBestsellers()
    hu_to_bs_obj.homepageuselling_to_bestsellers()
    print "Data Copied"

错误

ImportError: No module named cartridge.shop.models

Answer 1

您正在使用Django 1.4所以这是编写环境的正确方法..

import os
import sys
os.environ.setdefault("DJANGO_SETTINGS_MODULE", "your_project_name.settings")

# you can import your model here and the locaion of function 
from your_project_name.models import Location

# From here you can start your script..

Answer 2

在我看来（特别是考虑到你的用例）这样做的最好方法是编写自己的管理命令。子类Basecommand然后将其作为

运行

 python manage.py yourcommand arguments

Django documentation for custom commands

运行Standalone脚本Django

2 个答案: