Question

我的任务是将JSON解析为可以创建表单的对象。这个表格里面可以有子表格，这是我遇到困难的一步。考虑这个JObject，它是子表单的表示，因为主表单已经反序列化，现在作为JObject传递：

  {
  "3705": {
    "type": "radioGroup",
    "label": "Loft Insulation Applicable",
    "default_value": null,
    "order": "2",
    "required": "false",
    "security": "false",
    "option": null,
    "child": [
      {
        "type": "radio",
        "label": "No",
        "order": "3"
      },
      {
        "type": "radio",
        "label": "Yes",
        "order": "4"
      }
    ]
  },
  "3708": {
    "type": "input",
    "label": "Existing Depth (mm)",
    "default_value": null,
    "order": "5",
    "required": "false",
    "security": "false",
    "option": null
  },
  "3709": {
    "type": "input",
    "label": "Required Depth (mm)",
    "default_value": null,
    "order": "6",
    "required": "false",
    "security": "false",
    "option": null
  },
  "3715": {
    "type": "radioGroup",
    "label": "Total Pipework Meterage",
    "default_value": null,
    "order": "16",
    "required": "false",
    "security": "false",
    "option": null,
    "child": [
      {
        "type": "radio",
        "label": "15 mm",
        "order": "17"
      },
      {
        "type": "radio",
        "label": "22 mm",
        "order": "18"
      },
      {
        "type": "radio",
        "label": "28 mm",
        "order": "19"
      }
    ]
  },
  "3719": {
    "type": "formLabel",
    "label": "Loft Access Requirements",
    "default_value": null,
    "order": "20",
    "required": "false",
    "security": "false",
    "option": null
  },
  "3720": {
    "type": "radioGroup",
    "label": "Crawlers",
    "default_value": null,
    "order": "21",
    "required": "false",
    "security": "false",
    "option": null,
    "child": [
      {
        "type": "radio",
        "label": "No",
        "order": "22"
      },
      {
        "type": "radio",
        "label": "Yes",
        "order": "23"
      }
    ]
  },
  "3723": {
    "type": "radioGroup",
    "label": "Cavity Ladders for Loft",
    "default_value": null,
    "order": "24",
    "required": "false",
    "security": "false",
    "option": null,
    "child": [
      {
        "type": "radio",
        "label": "No",
        "order": "25"
      },
      {
        "type": "radio",
        "label": "Yes",
        "order": "26"
      }
    ]
  },
  "3726": {
    "type": "image",
    "label": "Loft Photos",
    "default_value": null,
    "order": "27",
    "required": "false",
    "security": "false",
    "option": null
  }
}

我正在尝试将其反序列化为此类中定义的类型对象列表：

public class DBFormField
{
    public string type { get; set; }
    public string label { get; set; }
    public string default_value { get; set; }
    public string order { get; set; }
    public string required { get; set; }
    public DBFormFieldOption option = new DBFormFieldOption();
    public List<DBFormFieldChild> child = new List<DBFormFieldChild>();
}

public class DBFormFieldOption
{
    public List<DBFormFieldGrid> grid_rows = new List<DBFormFieldGrid>();
    public List<DBFormFieldGrid> grid_columns = new List<DBFormFieldGrid>();
    public string label1 { get; set; }
    public string label2 { get; set; }
    public string result_label { get; set; }
    public string operation { get; set; }
    public List<string> rows = new List<string>();
    public string tab_id { get; set; }
}

public class DBFormFieldChild
{
    public string type { get; set; }
    public string label { get; set; }
    public string order { get; set; }
}

public class DBFormFieldGrid
{
    public string title { get; set; }
    public string name { get; set; }
}

我尝试了一些策略来做到这一点。最新的，我正在尝试这个http://james.newtonking.com/json/help/CustomCreationConverter

例如：

List<DBFormField> parsedFields = new List<DBFormField>();
parsedFields = JsonConvert.DeserializeObject<List<DBFormField>>(someFormObj.form_fields.ToString, new FormConverter());  // ToString???

... 公共类FormConverter Inherits Converters.CustomCreationConverter（Of DBFormField）

    Public Overrides Function Create(objectType As Type) As DBFormField
        Return New DBFormField()
    End Function
End Class

我怀疑将.ToString放在JObject的末尾对于DeserializeObject方法来说还不够好？见上面的评论。但是这段代码会引发错误......

无法反序列化当前的JSON对象（例如{“name”：“value”}）进入类型'System.Collections.Generic.List`1 [RSAP.DBFormField]' 因为该类型需要一个JSON数组（例如[1,2,3]）来反序列化正确。

我还没有尝试将JObject序列化为JSON字符串 - 考虑到我们已经将JSON解析为Jobject，这似乎很糟糕。

Answer 1

您在json中有单个对象，并且您尝试将其反序列化为对象列表 - 这是无法完成的。

解决方案：

您可以通过在对象

[

]

您可以反序列化为单个对象（不是列表）：

JsonConvert.DeserializeObject<DBFormField>(someFormObj.form_fields.ToString(), new FormConverter());
您可以反序列化单个对象并将其添加到列表中：

List<DBFormField> parsedFields = new List<DBFormField>(); parsedField = JsonConvert.DeserializeObject<DBFormField>someFormObj.form_fields.ToString(), new FormConverter()); parsedFields.Add(parsedField);

将JObject反序列化为.NET对象列表

1 个答案: