插入准备语句错误

时间:2014-08-13 18:16:43

标签: php mysql prepared-statement

我第一次尝试使用预备语句以避免sql注入但是当我尝试插入或更新我的数据库时我似乎有问题我使用这些行来做我想要的:

插入:

 $stmt = $con->prepare("INSERT INTO my_array (image1,image2,image3,image4, info, type, lat, lng, date_created, status, created_by, closed_by, date_finished) VALUES ( ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)") ;

$stmt->bind_param('bbbbssddsssss', $image1, $image2, $image3, $image4, $info, $type, $lat, $long, $date, $opened, $user, $closed_by, $closed_by, $date_finished);

$stmt->execute();

$result = $stmt->get_result();

更新

$stmt = $con->prepare("UPDATE users SET fullname =  IF(LENGTH(?) = 0, fullname, ?), email = IF(LENGTH(?) = 0, email, ?), phone_num = IF(LENGTH(?) = 0, phone_num, ?) , address = IF(LENGTH(?) = 0, address, ?)  WHERE username = '$user'") ;

$stmt->bind_param('ssssiiss',$fullname, $fullname, $email, $email, $phone_number , $phone_number, $address, $address);

$stmt->execute();

$result = $stmt->get_result();

两者都得到“假”结果。

2 个答案:

答案 0 :(得分:0)

首先,你有$closed_by副本。

在第二个中,您在准备好的声明中有$user。那必须是一个参数。

答案 1 :(得分:0)

在每个陈述中使用正确的错误处理:

if(!($stmt = $con->prepare("INSERT INTO my_array (image1,image2,image3,image4, info, type, lat, lng, date_created, status, created_by, closed_by, date_finished) VALUES ( ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)"))
{
     echo "Prepare failed: (" . $con->errno . ") " . $con->error;
}

if(!$stmt->bind_param('bbbbssddsssss', $image1, $image2, $image3, $image4, $info, $type, $lat, $long, $date, $opened, $user, $closed_by, $closed_by, $date_finished))
{
      echo "Binding parameters failed: (" . $stmt->errno . ") " . $stmt->error;
}

if(!$stmt->execute())
{
      echo "Execute failed: (" . $stmt->errno . ") " . $stmt->error;
}

if(!($result = $stmt->get_result())
{
      echo "Getting result set failed: (" . $stmt->errno . ") " . $stmt->error;
}
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