Mysql-从两个表中选择查询

时间:2014-08-14 06:10:14

标签: mysql

我有两个表item_info和item_log表如下:

Item_info

Item_log

现在我需要搜索'like'item_name,结果将显示任何item_id的最后一行,如:

Result

4 个答案:

答案 0 :(得分:1)

你可以尝试这样的事情:

SELECT table1。*,MAX(table1.id)AS last_id,

table2table2.id

FROM(table1

加入table2 table1table2.id = table2table2.id

WHERE item_name LIKE'%nameOfItem%'

GROUP BY table1table2.id

ORDER BY table1id desc

它与我的函数有点相似,我必须为每个线程检索最近的消息。所以我必须加入表并按消息ID分组,并按消息发送的降序排列。

基本上,逻辑是完全相同的。如果它不起作用,请告诉我

答案 1 :(得分:1)

解决问题

SELECT item_log.*,item_info.name
FROM (item_log)
JOIN item_infos ON item_log.item_id = item_infos.item_id
WHERE id IN (SELECT MAX( item_log.id )
FROM (item_log)
JOIN item_infos ON item_log.item_id = item_infos.item_id
WHERE item_name LIKE '%G%'
GROUP BY item_log.item_id
ORDER BY item_log.id desc)
AND item_name LIKE '%G%'
GROUP BY item_log.item_id
ORDER BY item_log.id desc

答案 2 :(得分:0)

SELECT 
  * 
FROM
  (SELECT 
    item_info.`item_name`,
    item_log.`item_id`,
    item_log.`id`,
    item_log.`item_barcode`,
    item_log.`buy_price` 
  FROM
    item_log,
    item_info 
  WHERE item_info.`item_id` = item_log.`item_id` 
  ORDER BY id DESC) AS i 
GROUP BY item_id ;




I think this is what you are expecting right ?

答案 3 :(得分:0)

这可能适合您:

SELECT l.id,i.item_id,l.item_barcode,i.item_name,l.buy_price 
FROM item_info i 
LEFT JOIN item_log l  ON i.item_id=l.item_id 
WHERE  i.item_name LIKE '%G%'  
ORDER BY l.id desc  
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