Question

有谁能告诉我如何将这个网格读入像[i] [j]这样的数组？我在谷歌搜索但我似乎无法找到任何有用的东西。非常感谢您的帮助！

static void Main(string[] args)
    {
       String grid =    "08 02 22 97 38 15 00 40 00 75 04 05 07 78 52 12 50 77 91 08" +
                        "49 49 99 40 17 81 18 57 60 87 17 40 98 43 69 48 04 56 62 00" +
                        "81 49 31 73 55 79 14 29 93 71 40 67 53 88 30 03 49 13 36 65" +
                        "52 70 95 23 04 60 11 42 69 24 68 56 01 32 56 71 37 02 36 91" +
                        "22 31 16 71 51 67 63 89 41 92 36 54 22 40 40 28 66 33 13 80" +
                        "24 47 32 60 99 03 45 02 44 75 33 53 78 36 84 20 35 17 12 50" +
                        "32 98 81 28 64 23 67 10 26 38 40 67 59 54 70 66 18 38 64 70" +
                        "67 26 20 68 02 62 12 20 95 63 94 39 63 08 40 91 66 49 94 21" +
                        "24 55 58 05 66 73 99 26 97 17 78 78 96 83 14 88 34 89 63 72" +
                        "21 36 23 09 75 00 76 44 20 45 35 14 00 61 33 97 34 31 33 95" +
                        "78 17 53 28 22 75 31 67 15 94 03 80 04 62 16 14 09 53 56 92" +
                        "16 39 05 42 96 35 31 47 55 58 88 24 00 17 54 24 36 29 85 57" +
                        "86 56 00 48 35 71 89 07 05 44 44 37 44 60 21 58 51 54 17 58" + 
                        "19 80 81 68 05 94 47 69 28 73 92 13 86 52 17 77 04 89 55 40" +
                        "04 52 08 83 97 35 99 16 07 97 57 32 16 26 26 79 33 27 98 66" +
                        "88 36 68 87 57 62 20 72 03 46 33 67 46 55 12 32 63 93 53 69" +
                        "04 42 16 73 38 25 39 11 24 94 72 18 08 46 29 32 40 62 76 36" +
                        "20 69 36 41 72 30 23 88 34 62 99 69 82 67 59 85 74 04 36 16" +
                        "20 73 35 29 78 31 90 01 74 31 49 71 48 86 81 16 23 57 05 54" +
                        "01 70 54 71 83 51 54 69 16 92 33 48 61 43 52 01 89 19 67 48";

     int[] a = new int[20];

        for(int i=0;i<20;i++)
            for (int j = 1; j < 20; j++)
            {

            }


    }

Answer 1

根据评论中的建议，您可以简单地分隔您的数字并使用拆分字符串。例如：

    private static void Main(string[] args)
    {
        String grid = "08,02,22,97,38,15,00,40,00,75,04,05,07,78,52,12,50,77,91,08," +
                      "49,49,99,40,17,81,18,57,60,87,17,40,98,43,69,48,04,56,62,00," +
                      "81,49,31,73,55,79,14,29,93,71,40,67,53,88,30,03,49,13,36,65," +
                      "52,70,95,23,04,60,11,42,69,24,68,56,01,32,56,71,37,02,36,91," +
                      "22,31,16,71,51,67,63,89,41,92,36,54,22,40,40,28,66,33,13,80," +
                      "24,47,32,60,99,03,45,02,44,75,33,53,78,36,84,20,35,17,12,50," +
                      "32,98,81,28,64,23,67,10,26,38,40,67,59,54,70,66,18,38,64,70," +
                      "67,26,20,68,02,62,12,20,95,63,94,39,63,08,40,91,66,49,94,21," +
                      "24,55,58,05,66,73,99,26,97,17,78,78,96,83,14,88,34,89,63,72," +
                      "21,36,23,09,75,00,76,44,20,45,35,14,00,61,33,97,34,31,33,95," +
                      "78,17,53,28,22,75,31,67,15,94,03,80,04,62,16,14,09,53,56,92," +
                      "16,39,05,42,96,35,31,47,55,58,88,24,00,17,54,24,36,29,85,57," +
                      "86,56,00,48,35,71,89,07,05,44,44,37,44,60,21,58,51,54,17,58," +
                      "19,80,81,68,05,94,47,69,28,73,92,13,86,52,17,77,04,89,55,40," +
                      "04,52,08,83,97,35,99,16,07,97,57,32,16,26,26,79,33,27,98,66," +
                      "88,36,68,87,57,62,20,72,03,46,33,67,46,55,12,32,63,93,53,69," +
                      "04,42,16,73,38,25,39,11,24,94,72,18,08,46,29,32,40,62,76,36," +
                      "20,69,36,41,72,30,23,88,34,62,99,69,82,67,59,85,74,04,36,16," +
                      "20,73,35,29,78,31,90,01,74,31,49,71,48,86,81,16,23,57,05,54," +
                      "01,70,54,71,83,51,54,69,16,92,33,48,61,43,52,01,89,19,67,48";

        var splitstring = grid.Split(',');
        var a = new int[20,20];

        const int rowCount = 19; //counts 0 as 1
        var rowIndex = 0;
        var colIndex = 0;

        foreach (var s in splitstring)
        {
            if (rowIndex > rowCount)
            {
                rowIndex = 0;
                colIndex++;
            }
            a[colIndex, rowIndex] = Int32.Parse(s);
            rowIndex++;
        }
    }

注意，如果解析失败，Int32.Parse(s)将抛出异常。您可以使用Int32.TryParse并使用out值作为结果。取决于你想做什么。

Answer 2

考虑在每个＆＃34;行的末尾添加一个空格＆＃34;如下：

String grid =    "08 02 .. 91 08 " +
                 "01 70 .. 67 48 ";
                             // ^-- add space here

这将允许将字符串简单地转换为带有string.Split的1D字符串数组。

string grid = "08 02 .. 91 08";       // every number is space-separated now
string[] gridArray = grid.Split(" "); // -> ["08", "02", .. "91", "08"]

（即使没有确保额外的空格，也可以使用正则表达式拆分来实现一维数组：var gridArray = Regex.Split(grid, "(?:\s|(?<=\d{2})(?=\d{2}))")，但我建议＆＃34;标准化＆＃34;输入字符串文字，如果可能的话。）

生成的1D数组中的每个索引都可以这样访问，其中columns表示超强矩阵的列数，或者＃34;宽度＆＃34;每一行。

int columns = 20;
int gridIndex = j * columns + i;      // where j is a *row* and i is a *column*
                                      // for a column-major matrix
string numStr = gridArray[gridIndex]; // and value at the [column,row]

然后，只需将numStr转换为整数并将其分配给相应的数组索引即可。

如果每个数字都被一个空格分隔，那么NN的形式就是NN＆＃34; NN＆＃34;它也占用3个字符。在这种情况下，可以跳过中间分割，使用与作为一维序列索引到源中相同的想法。

int gridNumOffset = (j * columns + i) * 3;
string numStr = grid.Substring(gridNumOffset, 2);

（即使在行尾有 no 空格时也能找到子串偏移量，可以使用更多的数学运算来完成，这是一个很好的练习，公式变为{{ 1}}，其中(j * columns + i) * 3 + f(i)应用适当的偏移量。）

另一个更普通的方法，假设原始字符串不能被修改为包含行尾空格/字符，就是在每行中读取N个字符，处理它并继续前进。可以应用上面的概念：

f(i)

将数字串读入网格/矩阵

2 个答案: