Question

如果我使用下面的代码（来自http://doc.akka.io/docs/akka/2.0/scala/routing.html），routees如何引用/ router2（不使用sender()），context.parent 1}}不起作用？

val actor1 = system.actorOf(Props[ExampleActor1])
val actor2 = system.actorOf(Props[ExampleActor1])
val actor3 = system.actorOf(Props[ExampleActor1])
val routees = Vector[ActorRef](actor1, actor2, actor3)
val router2 = system.actorOf(Props[ExampleActor1].withRouter(
RoundRobinRouter(routees = routees)))

Answer 1

正如您目前所写的那样，他们无法做到。您必须明确地将路由器的ActorRef传递给路由器。

另一个选择是让路由器创建其路由，然后路由＆＃39; context.parent将引用路由器。

Answer 2

如果你真的希望一个白痴能够通过路由器与其他路由进行通信，那么你可以在创建所有内容后将路由器（引入它）作为消息发送到路由中。从那里，您可以通过路由器广播消息以将其发送到所有路由，但请记住，广播保证人也将收到相同的消息。像这样：

object MyActor{
  case class SetParent(ref:ActorRef)
  case class OtherMessage(s:String)
} 

class MyActor extends Actor{
  import MyActor._

  def receive = myReceive()

  def myReceive(parentOpt:Option[ActorRef] = None):Receive = {
    case SetParent(parent) => context.become(myReceive(Some(parent)))
    case OtherMessage(msg) => println(s"Got other message: $msg")
    case someOtherMsg => 
      parentOpt foreach (parent => Broadcast(OtherMessage("hello world")))
  }
}

然后，您的actor创建逻辑如下所示：

val actor1 = system.actorOf(Props[ExampleActor1])
val actor2 = system.actorOf(Props[ExampleActor1])
val actor3 = system.actorOf(Props[ExampleActor1])
val routees = Vector[ActorRef](actor1, actor2, actor3)
val router2 = system.actorOf(Props[ExampleActor1].withRouter(
  RoundRobinRouter(routees = routees)))
routees foreach (r => r ! SetParent(router))

路由引用路由器

2 个答案: