Question

我试图将使用itertools库的Python函数转换为VB.Net：

permutations = itertools.product('ab', repeat=3)

上述函数返回所有排列：

[['a','a','a'],
 ['a','a','b'],
 ['a','b','a'],
 ['a','b','b'],
 ['b','a','a'],
 ['b','a','b'],
 ['b','b','a'],
 ['b','b','b']]

在VB.Net中有一个很好的干净方法吗？

Answer 1

如果我没有弄错的话，你的问题的答案。 - https://stackoverflow.com/a/21090635/2319909

Answer 2

我最终将python itertools.product函数转换为vb.net：

Function Permute (chars As List (Of Char), len As Integer) As List (Of List (Of Char))
    Dim pools As New List (Of List (Of Char))
    Dim result As New List (Of List (Of Char)) From {New List (Of Char)}
    For i = 0 To len - 1
        pools.Add (chars)
    Next
    For Each pool As List (Of Char) In pools
        Dim result2 As New List (Of List (Of Char))
        For Each x In result
            For Each y In pool
                Dim temp As New List (Of Char)(x)
                temp.Add (y)
                result2.Add (temp)
            Next
        Next
        result = New List (Of List (Of Char))(result2)
    Next
    Return result
End Function

为给定长度和字符集生成所有可能的排列

2 个答案: