Question

我想为我的托管公司报价。我提出了一个表格：

CREATE TABLE `planes` (
  `id` int(5) unsigned NOT NULL auto_increment,
  `DiskSpace` text NOT NULL,
  `AnnuallyDataTransfer` text NOT NULL,
  `FTPAccounts` text NOT NULL,
  `EmailBoxes` text NOT NULL,
  `BandwidthAllowance` text NOT NULL,
  `FreeDomains` text NOT NULL,
  `MySQLDatabases` text NOT NULL,
  `price` text NOT NULL,
  PRIMARY KEY  (`id`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8 AUTO_INCREMENT=3 ;


INSERT INTO `planes` VALUES (1, '5GB', 'Unlimited', '25', '1000', 'Unlimited', '1', 'Unlimited', '200 LE');
INSERT INTO `planes` VALUES (2, '10 GB', 'Unlimited', '50', '1000', 'Unlimited', '1', 'Unlimited', '300');

然后我尝试在php代码中显示这些优惠。这是代码：

<?php
    $result = mysql_query("SELECT * FROM planes ORDER BY id DESC LIMIT 0,2") or die(mysql_error());
    $Disc = 1;
    echo '<table class="ranking">';
    echo '<tr><td class="rankhead">#</td><td class="rankhead">Plan1</td><td class="rankhead">Plan2</td><td class="rankhead">plan3</td></tr>';
    while($row = mysql_fetch_array( $result )){
        $name =  $row['AnnuallyDataTransfer'];
        $Disc = $row['FTPAccounts'];
        $class = $row['EmailBoxes'];

        echo '<tr>';
        echo '<td class="rankvalues">'.$Disc.'</td>';
        echo '<td class="rankvalues">'.$name.'</td>';
        echo '<td class="rankvalues">'.$Disc.'</td>';
        echo '<td class="rankvalues">'.$class.'</td>';

        $Disc++;
        echo "</tr>"; 
    }
    echo "</table>";
?>

但是我得到了错误设计。我希望将所有商品字段显示在左侧作为列并提供行，每个商品的价值来自左侧字段。

Answer 1

您使用$Disc变量进行此类增量，数据库值更正

试试这个

while($row = mysql_fetch_array( $result )){
      $AnnuallyDataTransfer =  $row['AnnuallyDataTransfer'];
      $FTPAccounts = $row['FTPAccounts'];
      $EmailBoxes = $row['EmailBoxes'];

      echo '<tr>';
      echo '<td class="rankvalues">'.$Disc.'</td>';
      echo '<td class="rankvalues">'.$AnnuallyDataTransfer.'</td>';
      echo '<td class="rankvalues">'.$FTPAccounts.'</td>';
      echo '<td class="rankvalues">'.$EmailBoxes.'</td>';

      $Disc++;
      echo "</tr>"; 
}

注意： mysql_*已被弃用[{1}}或mysqli_*

将数据库信息提取到表中

1 个答案: