Question

不管我给出什么输入我得到输出＆＃34;我想你已经老去冒险了。你的冒险在这里结束。＆＃34; 就像我输入17一样，我得到了＃34;我想你已经老去冒险了。你的冒险在这里结束。＆＃34;如果我输入18-59我会得到＆＃34;我认为你已经老去冒险了。你的冒险在这里结束。＆＃34;

while True:
    age = raw_input("\n So tell me " + str(name) + ", how old are you?: ")
    if age.isdigit() == False:
        print "\n Please, put only in numbers!"
        time.sleep(3)
    elif age < 18:
        print "\n %s. A minor. You got to be atleast 18 to go on this adventure. Your adventure ends here." % age
        time.sleep(7)
        exit(0) 
    elif age >= 60:
        print "\n %s. I think you're to old to go on an adventure. Your adventure ends here." % age
        time.sleep(5)
        exit(0)
    else:
        print "\n %s. You're starting to get old." % age
        break

Answer 1

您需要将输入与int

进行比较

age = int(raw_input("\n So tell me " + str(name) + ", how old are you?: "))

否则，您要将str与int进行比较。请参阅以下示例

>>> 5 < 10
True
>>> type(5)
<type 'int'>

>>> '5' < 10
False
>>> type('5')
<type 'str'>

在Python 2.x中，比较不同类型的值通常会忽略这些值并改为比较类型。因为str >= int，任何字符串都是>=任何整数。在Python 3.x中，你得到一个TypeError，而不是默默地做一些令人困惑和难以调试的事情。

Answer 2

问题是raw_input总是返回一个字符串对象，而那些并不真正与int类型进行比较。你需要进行一些类型转换。

如果您想使用isdigit来测试输入是否为数字，那么您应该采用以下方式：

while True:
    age = raw_input("\n So tell me " + str(name) + ", how old are you?: ")
    if age.isdigit() == False:
        print "\n Please, put only in numbers!"
        time.sleep(3)
    elif int(age) < 18:
        print "\n %s. A minor. You got to be atleast 18 to go on this adventure. Your adventure ends here." % age
        time.sleep(7)
        exit(0) 
    elif int(age) >= 60:
        print "\n %s. I think you're to old to go on an adventure. Your adventure ends here." % age
        time.sleep(5)
        exit(0)
    else:
        print "\n %s. You're starting to get old." % age
        break

但是，您可以通过立即转换为整数来简化代码，如果它是无效的字符串，只需捕获异常：

while True:
    try:
        age = int(raw_input("\n So tell me " + str(name) + ", how old are you?: "))
        if age < 18:
            print "\n %s. A minor. You got to be atleast 18 to go on this adventure. Your adventure ends here." % age
            time.sleep(7)
            exit(0) 
        elif age >= 60:
            print "\n %s. I think you're to old to go on an adventure. Your adventure ends here." % age
            time.sleep(5)
            exit(0)
        else:
            print "\n %s. You're starting to get old." % age
            break
    except ValueError:
        print "\n Please, put only in numbers!"
        time.sleep(3)

虽然raw_input的循环在Python中给出了奇怪的输出

2 个答案: