Question

我目前正在尝试制作一个打开，关闭，打开和关闭“洗碗机”的程序。当我运行这个程序一次时，我得到了我想要的结果：

Welcome to SiriWash
What would you like to do?
Open Door | Close Door | Turn on | Turn Off 
open door
opening door
The Dishwasher is Open and Off
What would you like to do?
Open Door | Close Door | Turn on | Turn Off

如果我再次这样做，我会得到：

Welcome to SiriWash
What would you like to do?
Open Door | Close Door | Turn on | Turn Off 
open door
opening door
The Dishwasher is Open and Off
What would you like to do?
Open Door | Close Door | Turn on | Turn Off 
close door
What would you like to do?
Open Door | Close Door | Turn on | Turn Off

这是Runner Code：

import java.util.Scanner;

public class Runner {

    public static void main(String[] args) {
        Scanner reader = new Scanner(System.in);
        boolean gameRunning = true;
        Dishwasher washer1 = new Dishwasher(false,false);
        washer1.open();
        washer1.turnOff();
        //System.out.println(washer1);
        System.out.println("Welcome to SiriWash");
        String answer = "";
        //String answer = "";
        while (gameRunning) {
            System.out.println("What would you like to do?");
            System.out.println("Open Door | Close Door | Turn on | Turn Off ");
            answer = reader.nextLine();
            if (answer.equalsIgnoreCase("open door")) {
                washer1.open();
                System.out.println("opening door");
                System.out.println(washer1);
                answer = "";
            if (answer.equalsIgnoreCase("close door")) {
                washer1.close();
                System.out.println("Closing door");
                System.out.println(washer1);
                answer = "";
            if (answer.equalsIgnoreCase("turn on")) {
                washer1.turnOn();
                System.out.println("turning on");
                System.out.println(washer1);
                answer = "";
            if (answer.equalsIgnoreCase("turn off")){
                washer1.turnOff();
                System.out.println("turning off");
                System.out.println(washer1);
                answer = "";
            }
            }
            }
            }
        }
    }   
}

似乎在第二次输入时会跳过if语句，我该如何解决？

Answer 1

所有if都是嵌套的，所以如果第一次失败，则会跳过所有其余的if。尝试在每个if( condition1 ){ body } if( condition2 ){ body2 } ...主体之后关闭花括号：

{{1}}

如果在While循环中的语句

1 个答案: