Question

我有一个XML文件，如下所示：

<tagA key1="val1" key2="val2" key3="val3">
<tagB.1 key1="val1" key2="val2" key3="val3"/>
<tagB.2 key1="val1" key2="val2" key3="val3"/>
<tagB.3 key1="val1" key2="val2" key3="val3"/>
<tagB.4 key1="val1" key2="val2" key3="val3"/>
<tagB.5 key1="val1" key2="val2" key3="val3"/>
</tagA>

我要做的是在key1中提取key2，key3和tagB.x的名称，并将它们放入列表中。这样我以后可以提取它的值。它应该能够处理更多或更少的元素，因为每个文件都是不同的。谢谢！

Answer 1

您应该使用xml解析器：

xml="""
<tagA key1="val1" key2="val2" key3="val3">
<tagB.1 key1="val1" key2="val2" key3="val3"/>
<tagB.2 key1="val1" key2="val2" key3="val3"/>
<tagB.3 key1="val1" key2="val2" key3="val3"/>
<tagB.4 key1="val1" key2="val2" key3="val3"/>
<tagB.5 key1="val1" key2="val2" key3="val3"/>
</tagA>
"""


import xml.etree.ElementTree as ET

root = ET.fromstring(xml)
for child in root:
    print child.tag, child.attrib.keys()

tagB.1 ['key3', 'key2', 'key1']
tagB.2 ['key3', 'key2', 'key1']
tagB.3 ['key3', 'key2', 'key1']
tagB.4 ['key3', 'key2', 'key1']
tagB.5 ['key3', 'key2', 'key1']

使用Beautiful Soup查找XML中的所有属性

1 个答案: