如何使用2个不同的列表序列化XML文档?

时间:2014-08-26 13:31:00

标签: c# xml list serialization asp-classic

好的我正在使用ASP MVC并且正在尝试加载一些我需要序列化的XML数据,因为我将它转换为JSON。

我无法理解的是,我的XML有多个后代。那么,当我序列化它时,在模型中我需要将每个后代的数据存储在它自己的列表中吗?

我已经做到了,所以我有两个单独的名单。那么,我如何将这一切都序列化为一个XML文档?

这是我的XML标记的一个例子:

<vehicle>
<make>Suzuki</make>
<color>Yellow></color>
<owner>
    <id>0</id>
    <name>Joe Bloggs</name>
</owner>
<owner>
    <id>1</id>
    <name>Foo Bar</name>
</owner>
</vehicle>

这是我的XML模型:

    public partial class vehicle
    {
        private string makeField;
        private string colorField;

        private vehicleOwner[] ownerField;

        /// <remarks/>
        public string make {get; set;}

        /// <remarks/>
        public string color{get; set;}

        [System.Xml.Serialization.XmlElementAttribute("owner")]
        public vehicleOwner[] owner{ get; set;}

        // Keep this in a list to serialize it
        List<vehicle> vehicleList = new List<vehicle>();
    }

    /// <remarks/>
    [System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
    public partial class vehicleOwner
    {

        private int idField;

        private string nameField;


        /// <remarks/>
        public int id { get; set;}


        /// <remarks/>
        public string nameField {get; set;}


        // Stick it in a list so I can serialize it later
        List<vehicleOwner> vehicleOwnerList = new List<vehicleOwner>();
    }

}

所以,现在我有两个包含XML数据的列表:vehicleOwnerList和vehicleList。 但这些都是一个XML文档。那么如何为两个列表序列化这个?我是否必须将它们合并到一个列表中,如果是这样,我该怎么做?

所以I.E。

 List<vehicleOwner> listCombinedActions = new List<vehicleOwner>();

                XmlDocument xmlDoc = new XmlDocument();
                XPathNavigator nav = xmlDoc.CreateNavigator();
                using (XmlWriter writer = nav.AppendChild())
                {
                    XmlSerializer ser = new XmlSerializer(typeof(List<vehicle>), new XmlRootAttribute("owner"));
                    ser.Serialize(writer, listCombinedActions);
                }

干杯

1 个答案:

答案 0 :(得分:1)

我希望我明白你想要实现的目标,这样可以添加如何完成的例子:


数据模型:

//NOTE: property, root class names is different. 
//So you can name it what you want but you need to specify xml tag name in attribute

[XmlRoot("vehicle")]
public class vehicleObject
{
    public string make { get; set; }
    public string color { get; set; }

    [System.Xml.Serialization.XmlElement("owner")]
    public List<vehicleOwner> ownerList { get; set; }
}

public class vehicleOwner
{
    public int id { get; set; }

    [System.Xml.Serialization.XmlElement("name")]
    public string nameField { get; set; }
} 

用法:

vehicleObject yourWorkingObject;

using (MemoryStream ms = new MemoryStream(File.ReadAllBytes("c:\\a.xml")))
{
    XmlSerializer serializer = new XmlSerializer(typeof(vehicleObject));
    yourWorkingObject = serializer.Deserialize(ms) as vehicleObject;
}

//Do with yourWorkingObject here what you want

结果:

example

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