SQLiteException没有这样的表

时间:2014-09-02 18:57:02

标签: android-sqlite

刚刚开始Android,我正在尝试创建一个简单的应用程序,它有一个用于收集名称和联系人的SQLite数据库。我创建了一个视图活动,它将使用simpleCursorAdapter在列表视图中显示内容(是的,它已经折旧,但我还没有使用自定义适配器。无论如何,到目前为止,代码编译得很好。当我点击按钮开始时视图活动我得到了

SQLite异常:没有这样的表:clientTable(代码1):,编译时:SELECT _id,name,mobile FROM clientTable。

下面是我的数据库类的代码

package com.example.ideahutquizz;

import android.content.Context;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteOpenHelper;

public class ClientDatabase extends SQLiteOpenHelper {

    public static final String KEY_ROWID = "_id";
    public static final String KEY_NAME = "name";
    public static final String KEY_MOBILE = "mobile";

    public static final String DATABASE_NAME = "clientDatabase";
    public static final String TABLE_NAME = "clientTable";
    public static final int DATABASE_VERSION = 1;

    String CREATE_TABLE = "create table"
            + TABLE_NAME + "("
            + KEY_ROWID + "INTEGER PRIMARY KEY AUTOINCREMENT,"
            + KEY_NAME + "TEXT NOT NULL,"
            + KEY_MOBILE + "TEXT NOT NULL" + ")";

    public ClientDatabase(Context context) {
            super(context, DATABASE_NAME, null, DATABASE_VERSION);
        }

        @Override
        public void onCreate(SQLiteDatabase db) {
            // TODO Auto-generated method stub
            db.execSQL(CREATE_TABLE);
        }

        @Override
        public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
            // TODO Auto-generated method stub
            db.execSQL("DROP TABLE IF EXISTS " + TABLE_NAME);
            onCreate(db);
        }
}

以下是视图活动的代码

package com.example.ideahutquizz;

import android.content.Intent;
import android.database.Cursor;
import android.os.Bundle;
import android.support.v7.app.ActionBarActivity;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.ListView;
import android.widget.SimpleCursorAdapter;

public class ViewDataActivity extends ActionBarActivity {

    Button back;
    ListView clientList;
    SQLController clientDB;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_view_data);

        clientList = (ListView)findViewById(R.id.listView1);
        back = (Button)findViewById(R.id.button1);
        clientDB = new SQLController(this);
        clientDB.open();


        Cursor cursor = clientDB.readData();
        String[] from = new String[]{ClientDatabase.KEY_ROWID, ClientDatabase.KEY_NAME, ClientDatabase.KEY_MOBILE};
        int[] to = new int[]{R.id.textView_id, R.id.textView_name, R.id.textView_mobile};

        SimpleCursorAdapter adapter = new SimpleCursorAdapter(this, R.layout.listview_item_row, cursor, from, to);
        adapter.notifyDataSetChanged();
        clientList.setAdapter(adapter);

        back.setOnClickListener(new OnClickListener() {
            public void onClick(View v) {
                clientDB.close();
                Intent back = new Intent(ViewDataActivity.this, ControlPanel.class);
                startActivity(back);
            }
        });
    }

    @Override
    public boolean onCreateOptionsMenu(Menu menu) {
        // Inflate the menu; this adds items to the action bar if it is present.
        getMenuInflater().inflate(R.menu.view_data, menu);
        return true;
    }

    @Override
    public boolean onOptionsItemSelected(MenuItem item) {
        // Handle action bar item clicks here. The action bar will
        // automatically handle clicks on the Home/Up button, so long
        // as you specify a parent activity in AndroidManifest.xml.
        int id = item.getItemId();
        if (id == R.id.action_settings) {
            return true;
        }
        return super.onOptionsItemSelected(item);
    }
}

非常感谢任何帮助。

...更新

我按如下方式更改了create table语句,但我仍然遇到同样的错误......

private static final String CREATE_TABLE = 
        "create table " + TABLE_NAME + "("
        + KEY_ROWID + " integer primary key autoincrement,"
        + KEY_NAME + " text not null,"
        + KEY_MOBILE + " text not null" + ")";

2 个答案:

答案 0 :(得分:1)

未创建表:

    String CREATE_TABLE = "create table"
        + TABLE_NAME + "("

会产生这个字符串:

    String CREATE_TABLE = "create tableclientTable("

您需要在create table之后添加一个空格:

    String CREATE_TABLE = "create table "
        + TABLE_NAME + "("

字段名称

也是如此

所以,最后,字符串将是:

String CREATE_TABLE = "CREATE TABLE " +
    TABLE_NAME + " (" +
    KEY_ROWID + " INTEGER PRIMARY KEY AUTOINCREMENT, " +
    KEY_NAME + " TEXT NOT NULL, " +
    KEY_MOBILE + " TEXT NOT NULL" + ")";

答案 1 :(得分:1)

由于缺少空格,您的CREATE TABLE语句将失败;

String CREATE_TABLE = "create table"
        + TABLE_NAME + "("
        + KEY_ROWID + "INTEGER PRIMARY KEY AUTOINCREMENT,"
        + KEY_NAME + "TEXT NOT NULL,"
        + KEY_MOBILE + "TEXT NOT NULL" + ")";

...会产生类似

的内容
create tableclientTable(
    _idINTEGER PRIMARY KEY AUTOINCREMENT,
    nameTEXT NOT NULL,
    mobileTEXT NOT NULL)

...这会导致语法错误而不会创建表。

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