Question

我有一个问题：

WITH cte AS(
SELECT T3.DateTime AS AADateTime,
        (T3.In_Minbps/1000)/1000 AS MinReceiveMbps,
                (T3.In_Maxbps/1000)/1000 AS MaxReceiveMbps,
                (T3.In_Averagebps/1000)/1000 AS AvgReceiveMbps,
                (T3.Out_Minbps/1000)/1000 AS MinTransmitMbps,
                (T3.Out_Maxbps/1000)/1000 AS MaxTransmitMbps,
                (T3.Out_Averagebps/1000)/1000 AS AvgTransmitMbps
FROM dbo.Nodes AS T1
    INNER JOIN dbo.Interfaces AS T2 ON [T1].[NodeID] = [T2].[NodeID]
    INNER JOIN InterfaceTraffic AS T3 ON [T2].[InterfaceID] = [T3].[InterfaceID]
WHERE [T1].[Caption] = 'cust-firewall01' 
    AND [T2].[InterfaceName] = 'reth0' 
    AND DateTime >= '2014-08-01 00:00:00' AND DateTime <= '2014-08-31 23:59:59'
)
SELECT MIN(AADateTime) AS AADateTime,
        MIN(MinReceiveMbps) AS MinReceiveMbps,
        MAX(MaxReceiveMbps) AS MaxReceiveMbps,
        MIN(MinTransmitMbps) AS MinTransmitMbps,
        MAX(MaxTransmitMbps) AS MaxTransmitMbps,
        AVG(AvgTransmitMbps) AS AvgTransmitMbps,
        AVG(AvgReceiveMbps) AS AvgReceiveMbps
FROM cte

然而，上述查询可以返回所有记录的最小值/最大值/平均值，我需要做的是每天返回最小值/最大值/平均值。示例表数据是：

Date,                In_Minbps, In_Maxbps, In_Averagebps, Out_Minbps, Out_Maxbps, Out_Averagebps
2014-08-01 00:00:00, 403227.2, 3489988,    1986171,       6509198,    6.510824e+07, 33357.06
2014-08-01 01:00:00, 404039.1, 3626866,    2211984,       4491261,    6.61291e+07, 37061.19

我每天基本上每天需要24条记录：

SELECT MIN(AADateTime) AS AADateTime,
        MIN(MinReceiveMbps) AS MinReceiveMbps,
        MAX(MaxReceiveMbps) AS MaxReceiveMbps,
        MIN(MinTransmitMbps) AS MinTransmitMbps,
        MAX(MaxTransmitMbps) AS MaxTransmitMbps,
        AVG(AvgTransmitMbps) AS AvgTransmitMbps,
        AVG(AvgReceiveMbps) AS AvgReceiveMbps
FROM cte

Answer 1

SELECT CAST(Datetimefield AS DATE) AS Date,
        MIN(MinReceiveMbps) AS MinReceiveMbps,
        MAX(MaxReceiveMbps) AS MaxReceiveMbps,
        MIN(MinTransmitMbps) AS MinTransmitMbps,
        MAX(MaxTransmitMbps) AS MaxTransmitMbps,
        AVG(AvgTransmitMbps) AS AvgTransmitMbps,
        AVG(AvgReceiveMbps) AS AvgReceiveMbps
FROM cte
GROUP BY CAST(Datetimefield AS DATE)

按日期记录您的记录。

MS SQL查询每天最小/最大/平均值

1 个答案: