Question

我有以下地图：

def map = [[name:'Clark', city:'London'], [name:'Sharma', city:'London'], [name:'Maradona', city:'LA'], [name:'Zhang', city:'HK'],[name:'Ali', city: 'HK'], [name:'Liu', city:'HK']]

然后我按城市分组地图：

def mapGrouped = map.groupBy { it.city }

我得到以下输出：

[London:[[name:Clark, city:London], [name:Sharma, city:London]], LA:[[name:Maradona, city:LA]], HK:[[name:Zhang, city:HK], [name:Ali, city:HK], [name:Liu, city:HK]]]

我希望能删除例如 [姓名：阿里，城市：香港]

我知道如何完成这项任务？

Answer 1

由于地图已按城市分组，您可以按城市直接查找为关键字，并从表示为值的集合中删除所需的地图

def toRemove = [name:'Ali', city:'HK']
mapGrouped[toRemove.city] -= toRemove

println mapGrouped

当然，你可以确定你实际上正在寻找一个存在该群体的城市。

如何从嵌套地图中删除元素？

1 个答案: