如何使用camelCase将Hibernate实体字段映射到snake_case(下划线)数据库标识符

时间:2014-09-05 08:14:20

标签: java hibernate annotations

我在下划线中有数据库字段。我在camelcase中有实体字段。我不能改变其中任何一个。

是否有一些东西,也许是类级注释我可以用来默认实体列名注释到camelcase等价物?

例如,我有一个这样的实体:

@Entity
public class AuthorisationEntity {

    @Column(name = "non_recoverable")
    private BigDecimal nonRecoverable;

    @Column(name = "supplier_recoverable")
    private BigDecimal supplierRecoverable;

    @Column(name = "refund_amount")
    private BigDecimal refundAmount;

}

我梦见这个:

@Entity
@DatabaseIsUnderscoreAndThisAnnotationConvertsThemToCamelCaseByDefault
public class AuthorisationEntity {

    private BigDecimal nonRecoverable;

    private BigDecimal supplierRecoverable;

    private BigDecimal refundAmount;

}

4 个答案:

答案 0 :(得分:11)

您可以使用hibernate的命名策略。这种命名策略类描述了如何为给定的Java名称生成数据库名称。

请参阅:

naming strategy example

second example

very good oracle naming strategy - 它将驼峰转换为下划线约定,以及更多

答案 1 :(得分:6)

正如我在this article中所述,您可以使用自定义的Hibernate命名策略来实现这一目标。

您需要做的就是使用hibernate-types开源项目。

休眠5.2或更高版本

您需要添加以下Maven依赖项:

<dependency>
    <groupId>com.vladmihalcea</groupId>
    <artifactId>hibernate-types-52</artifactId>
    <version>${hibernate-types.version}</version>
</dependency>

并设置以下Hibernate配置属性:

<property name="hibernate.physical_naming_strategy"
          value="com.vladmihalcea.hibernate.type.util.CamelCaseToSnakeCaseNamingStrategy"
/>

休眠5.0和5.1

您需要添加以下Maven依赖项:

<dependency>
    <groupId>com.vladmihalcea</groupId>
    <artifactId>hibernate-types-5</artifactId>
    <version>${hibernate-types.version}</version>
</dependency>

并设置以下Hibernate配置属性:

<property name="hibernate.physical_naming_strategy"
          value="com.vladmihalcea.hibernate.type.util.CamelCaseToSnakeCaseNamingStrategy"
/>

休眠4.3

您需要添加以下Maven依赖项:

<dependency>
    <groupId>com.vladmihalcea</groupId>
    <artifactId>hibernate-types-43</artifactId>
    <version>${hibernate-types.version}</version>
</dependency>

并设置以下Hibernate配置属性:

<property name="hibernate.ejb.naming_strategy"
          value="com.vladmihalcea.hibernate.type.util.CamelCaseToSnakeCaseNamingStrategy"
/>

休眠4.2和4.1

您需要添加以下Maven依赖项:

<dependency>
    <groupId>com.vladmihalcea</groupId>
    <artifactId>hibernate-types-4</artifactId>
    <version>${hibernate-types.version}</version>
</dependency>

并设置以下Hibernate配置属性:

<property name="hibernate.ejb.naming_strategy"
          value="com.vladmihalcea.hibernate.type.util.CamelCaseToSnakeCaseNamingStrategy"
/>

测试时间

假设您具有以下实体:

@Entity(name = "BookAuthor")
public class BookAuthor {

    @Id
    private Long id;

    private String firstName;

    private String lastName;

    //Getters and setters omitted for brevity
}

@Entity(name = "PaperBackBook")
public class PaperBackBook {

    @Id
    @GeneratedValue(
        strategy = GenerationType.SEQUENCE
    )
    private Long id;

    @NaturalId
    private String ISBN;

    private String title;

    private LocalDate publishedOn;

    @ManyToOne(fetch = FetchType.LAZY)
    private BookAuthor publishedBy;

    //Getters and setters omitted for brevity
}

使用CamelCaseToSnakeCaseNamingStrategy自定义命名策略时,Hibernate将使用hbm2ddl工具生成以下数据库模式:

CREATE SEQUENCE hibernate_sequence
START WITH 1 INCREMENT BY 1

CREATE TABLE book_author (
    id          BIGINT NOT NULL,
    first_name  VARCHAR(255),
    last_name   VARCHAR(255),
    PRIMARY KEY (id)
)

CREATE TABLE paper_back_book (
    id              BIGINT NOT NULL,
    isbn            VARCHAR(255),
    published_on    DATE, 
    title           VARCHAR(255),
    published_by_id BIGINT, 
    PRIMARY KEY (id)
)

很酷,对吧?

答案 2 :(得分:1)

import org.hibernate.cfg.DefaultNamingStrategy;
import org.hibernate.cfg.ImprovedNamingStrategy;

public class NamingStratagyTest {
    public static void main(String[] args) {
        String colName = DefaultNamingStrategy.INSTANCE.columnName("UserName");
        System.out.println(colName); // UserName
        colName = ImprovedNamingStrategy.INSTANCE.columnName("UserName");
        System.out.println(colName);// user_name
    }
}

你去,选择适合你需要的命名策略。

答案 3 :(得分:0)

我在Spring启动应用程序中遇到了同样的问题,我尝试将上述Hibernate配置添加到spring属性文件中,但没有成功,将其添加为java bean,再次失败。

我正在使用Hibernate Properties对象,在其中添加了hibernate配置解决了我的问题:

        protected Properties buildHibernateProperties() {
        Properties hibernateProperties = new Properties();
        hibernateProperties.setProperty("hibernate.implicit_naming_strategy", SpringImplicitNamingStrategy.class.getName());
        hibernateProperties.setProperty("hibernate.physical_naming_strategy", SpringPhysicalNamingStrategy.class.getName());

        return hibernateProperties;
    }
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