Question

要在Rust中使用M:N线程模型，我会得到一个池，并且像往常一样开始生成任务。 The Green Documentation给出了以下示例：

#![feature(phase)]
#[phase(plugin)] extern crate green;

green_start!(main)

fn main() {
    // Running inside a green pool

    // Spawn more green threads?
    for x in some_thing.iter() {
        spawn(proc() {
            some_task()
        });
    }
}

如果你想动态添加另一个OS线程，可以这样做：

extern crate green;
extern crate rustuv;

use std::task::TaskBuilder;
use green::{SchedPool, PoolConfig, GreenTaskBuilder};

let mut config = PoolConfig::new();

// Optional: Set the event loop to be rustuv's to allow I/O to work
config.event_loop_factory = rustuv::event_loop;

let mut pool = SchedPool::new(config);

// Spawn tasks into the pool of schedulers
TaskBuilder::new().green(&mut pool).spawn(proc() {
    // this code is running inside the pool of schedulers

    spawn(proc() {
        // this code is also running inside the same scheduler pool
    });
});

// Dynamically add a new scheduler to the scheduler pool. This adds another
// OS thread that green threads can be multiplexed on to.
let mut handle = pool.spawn_sched();

// Pin a task to the spawned scheduler
TaskBuilder::new().green_pinned(&mut pool, &mut handle).spawn(proc() {
    /* ... */
});

// Handles keep schedulers alive, so be sure to drop all handles before
// destroying the sched pool
drop(handle);

// Required to shut down this scheduler pool.
// The task will fail if `shutdown` is not called.
pool.shutdown();

有没有办法说使用x num的OS线程，还是必须在代码中创建和管理它们？

Answer 1

根据PoolConfig的文档，在创建新池时可以指定操作系统线程的数量：

let mut config = PoolConfig::new();
config.threads = 42u;
let mut pool = SchedPool::new(config);
// use your pool with 42 OS threads as you want

config.threads的默认值由std::rt::default_sched_threads()

提供

管理绿色线程

1 个答案: