带有组的多个字段的Order By子句

时间:2014-09-08 23:51:59

标签: sql sql-server sql-order-by

我正在学习SQL。

我的表中有这些记录:

STUDENT_NAME    STATUS    CLASS_ID    ORDERING
----------------------------------------------
        Adam      'FR'          10           1
       Conan      'SE'           3           5
       Chris      'SE'           4           8 
       Louis      'JR'        null          10
        Dave      'JR'          14          17
       Alice      'SO'          14           8
        Paul      'SE'           4           6
         Tom      'SO'        null           3
        Eric      'FR'          14           5
       Blake      'JR'          11           2
        Ryan      'SE'           3          13
        Matt      'FR'        null          22

我希望通过ORDERING 订购,但我希望按其状态分组(就像具有相同状态的值一样)。

例如,结果如下所示:

STUDENT_NAME    STATUS    CLASS_ID    ORDERING
----------------------------------------------
        Adam      'FR'          10           1
        Eric      'FR'          14           5
        Matt      'FR'        null          22
       Blake      'JR'          11           2
       Louis      'JR'        null          10
        Dave      'JR'          14          17
         Tom      'SO'        null           3
       Alice      'SO'          14           8
       Conan      'SE'           3           5 // SAME CLASS_ID
        Ryan      'SE'           3          13
        Paul      'SE'           4           6 // SAME CLASS_ID
       Chris      'SE'           4           8 

Adam拥有最低的ORDERING值,因此他排名第一。但他的状态是' FR'所以下一个学生将是Eric,他的ORDERING低于Matt。

额外条件: 如果CLASS_ID不为null,我想根据CLASS_ID对其进行分组

是否可以通过条款' SELECT' ...' ORDER BY'来获得结果(请说是!)

我使用此查询,但效果不佳:

SELECT ... FROM STUDENTS stu
ORDER BY 
(SELECT MIN(S.ORDERING) FROM STUDENTS S WHERE S.STATUS = 'FR' AND stu.STATUS = 'FR'),
(SELECT MIN(S.CLASS_ID) FROM STUDENTS S WHERE S.CLASS_ID = stu.CLASS_ID),
stu.CLASS_ID ASC,
stu.ORDERING ASC

我也可以使用CASE子句。我需要你的帮助!

3 个答案:

答案 0 :(得分:2)

试试这个。我为MySQL写了这个,它也适用于SQL Server。它将NULL CLASS_IDS组合在一起(如果有的话)。我不会想到另一种方法。它给出了您正在寻找的结果。

SELECT stu.*

FROM STUDENTS stu

ORDER BY 
(SELECT MIN(S.ORDERING) FROM STUDENTS S WHERE S.STATUS = stu.STATUS),
(SELECT MIN(S.ORDERING) FROM STUDENTS S WHERE S.STATUS = stu.STATUS AND IFNULL(S.CLASS_ID, '') = IFNULL(stu.CLASS_ID, '')),
stu.ORDERING

SQL小提琴:sqlfiddle.com/#!2/a5a10/10/0

答案 1 :(得分:2)

你可以简单地做

SELECT * FROM students
ORDER BY STATUS, ORDERING, CLASS_ID

这里是fiddle

答案 2 :(得分:1)

听起来你想按每组最小的顺序排序

select s.* from students s
join (
    select status, min(ordering) min_status_ordering 
    from students group by status
) t1 on t1.status = s.status
join (
    select class_id, status, min(ordering) min_class_ordering 
    from students group by status, class_id
) t2 on (t2.class_id = s.class_id 
  or (t2.class_id is null and s.class_id is null))
  and t2.status = s.status                                  
order by t1.min_status_ordering, t2.min_class_ordering, s.ordering, s.status, s.class_id

http://sqlfiddle.com/#!2/f4eb4/2

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