Question

我是Matlab的新手，我无法有效地解决以下问题。

我有两个数组（两个都是2D），我想通过col检查array1 col，知道在array2的每个col中出现了多少个元素（比较col到col）

例如

array1

    ---------
    'a1'  'b1'    'c1'   
    'd1'  'e1'    'f1'

array2
----------
    'a1'   'a1'   'b1'  'b1'  'a1' 
    'd1'   'd1'   'c1'  'd1'  'c1'
    'c1'   'c1'   'b1'  'd1'  'd1'

我想获得以下输出

2 elements from array1 col1 appear in array2 col1
2 elements from array1 col1 appear in array2 col2
0 elements from array1 col1 appear in array2 col3
1 elements from array1 col1 appear in array2 col4
2 elements from array1 col1 appear in array2 col5

0 elements from array1 col2 appear in array2 col1
0 elements from array1 col2 appear in array2 col2
1 elements from array1 col2 appear in array2 col3
1 elements from array1 col2 appear in array2 col4
0 elements from array1 col2 appear in array2 col5

1 elements from array1 col3 appear in array2 col1
1 elements from array1 col3 appear in array2 col2
1 elements from array1 col3 appear in array2 col3
0 elements from array1 col3 appear in array2 col4
1 elements from array1 col3 appear in array2 col5
and so on

现在我尝试使用以下丑陋的代码获取部分输出

for i=1:size(Array1,2)
   for m=1:size(Array1,1)
     element = Array1(i,m);

     indx =find(ismember(Array2,element));
     Array_match(indx) = Array_match(indx) + 1;
     end
    for s=2:size(Array1,1)
    if  length(char(Array1(s,i))) > 0 
        tt= tt + 1;
    end
    length(Array_test_words(s,i))
    end
    Indx2 = find((Array_match) > tt);
 end

Answer 1

假设输入单元格数组包含单个字符串的所有单元格，这可能对您有用 -

%// Input cell arrays
array1 = {
    'a1' 'b1' 'c1'   
    'd1' 'e1' 'f1'}

array2 = {
        'a1'   'a1'   'b1'  'b1'  'a1' 
    'd1'   'd1'   'c1'  'd1'  'c1'
    'c1'   'c1'   'b1'  'd1'  'd1'}

%// Convert input cell arrays to numeric arrays
array1n = char(array1)-0
array1n = reshape(array1n(:,1) * 1000 + array1n(:,2),size(array1))

array2n = char(array2)-0
array2n = reshape(array2n(:,1) * 1000 + array2n(:,2),size(array2))

out = squeeze(sum(any(bsxfun(@eq,array2n,permute(array1n,[3 4 1 2])),1),3))

输出 -

out =
     2     0     1
     2     0     1
     0     1     1
     1     1     0
     2     0     1

Answer 2

将unique应用于两个数组的串联，以将单元格转换为数字标签。删除第二个数组的每列中的重复值。然后使用bsxfun测试相等性，并汇总每个列组合的结果：

[~, ~, labels] = unique({array1{:} array2{:}});
a1 = reshape(labels(1:numel(array1)),size(array1)); %// array1 as numeric labels
a2 = reshape(labels(numel(array1)+1:end), size(array2)); %// same for array2
a2 = sort(a2);
a2(diff([NaN(1,size(a2,2)); a2])==0) = NaN; %// remove repeated values
m = bsxfun(@eq, permute(a1, [1 3 2]), permute(a2, [3 1 4 2])); %// find matches
result = squeeze(sum(reshape(m, [],size(a1,2),size(a2,2)), 1));

在你的例子中，这给出了

result =
     2     2     0     1     2
     0     0     1     1     0
     1     1     1     0     1

比较并找到二维数组中的字符串

2 个答案: