在我的项目（Liferay Portlet）中，即时创建一个webservice-client。我在applicationContext.xml中定义了一个webServiceTemplate：
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:oxm="http://www.springframework.org/schema/oxm"
xsi:schemaLocation="http://www.springframework.org/schema/oxm http://www.springframework.org/schema/oxm/spring-oxm.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.2.xsd">
<context:annotation-config />
<context:component-scan base-package="be.icredit.einvoice.service, be.icredit.einvoice.webserviceTest" />
<oxm:jaxb2-marshaller id="marshaller" contextPath="be.icredit.einvoice.proxy.customerdaoservice"/>
<bean id="webServiceTemplate" class="org.springframework.ws.client.core.WebServiceTemplate">
<property name="marshaller" ref="marshaller" />
<property name="unmarshaller" ref="marshaller" />
<property name="defaultUri"
value="http://localhost:8081/ws-demo/account-balance-service" />
</bean>
</beans>
当我在CustomerClient.java中执行testFindCustomer方法时，我在webServiceTemplate上得到一个nullpointerexception。
public class CustomerClient extends WebServiceGatewaySupport {
@Autowired
private WebServiceTemplate webServiceTemplate;
private Log log = LogFactory.getLog(CustomerClient.class);
public CustomerClient()
{
}
public void testFindCustomer()
{
Find findCustomer = new Find();
findCustomer.setFilter(new CustomerFilter());
System.out.println(webServiceTemplate.getDefaultUri());
FindResponse response = (FindResponse) webServiceTemplate.marshalSendAndReceive(findCustomer);
ArrayList<Customer> list = (ArrayList) response.getReturn();
for(Customer c : list)
{
log.info("found");
}
}
这看起来非常基本，我不知道我做错了什么。 CustomerClient类位于be.icredit.einvoice.webserviceTest包中。
Nullpointerexceptions发生在System.out.println（webServiceTemplate.getDefaultUri（））;线。