Question

Hibernate抛出一个奇怪的错误

Hibernate：选择user0_.userID作为userID0_，user0_.password as 来自用户user0_的password0_，其中user0_.userID =＆＃39; admin＆＃39;和 user0_.password =＆＃39;管理＆＃39; org.hibernate.hql.ast.QuerySyntaxException：动作未映射[来自id =＆＃39; MADEX240214＆＃39;]的动作 org.hibernate.hql.ast.util.SessionFactoryHelper.requireClassPersister（SessionFactoryHelper.java:181）在 org.hibernate.hql.ast.tree.FromElementFactory.addFromElement（FromElementFactory.java:110）

我的代码有什么问题吗？

public String insertActions(ArrayList<Action> data , String[] check)
    {
    Session session = HibernateUtil.getSessionFactory().getCurrentSession();
    session.beginTransaction();
    Query query = null;
    try
    {
        for (int i = 0; i < data.size(); i++) 
        {
            if(check[i].compareTo("Update")==0)
            {
                query = session.createQuery("update Action set Last = :Last ,"
                        + " Adjusted_Last =:Adjusted_Last where idAction = :idAction");

                query.setDouble("Last", data.get(i).getLast());
                query.setDouble("Adjusted_Last", data.get(i).getAdjustLast());
                query.setParameter("idAction", data.get(i).getIdAction());
                int result = query.executeUpdate();
            }
            else
            {
                session.save(data.get(i));
            }
        }
    }
    catch (HibernateException e)
    {
        e.printStackTrace(); 
        session.getTransaction().rollback();
        return "ERROR";
    }
        session.getTransaction().commit();
        return "SUCCESS";
    }

Answer 1

从Hibernate 5.1开始，我们必须以这种方式编写HibernateUtil

public class HibernateUtil {

private static final SessionFactory SESSION_FACTORY;

static{
    try {
        StandardServiceRegistry serviceRegistry = new StandardServiceRegistryBuilder().configure().build();
        SESSION_FACTORY = new MetadataSources(serviceRegistry).buildMetadata().buildSessionFactory();
    } catch (Exception e) {
        throw new ExceptionInInitializerError(e);
    }
}
public static Session openSession() {
    return SESSION_FACTORY.openSession();
}

}

Answer 2

什么是完整的堆栈跟踪？它似乎不是来自该部分代码。错误是从“操作”中选择，而不是更新。

我注意到在您的更新语句中，您将表引用为“Action”。 HQL查询区分大小写。检查你的映射。 'action'！='行动'

Hibernate：未映射类

2 个答案: