Question

我的php脚本有问题。我需要它来获取有关用户的所有信息。我真的不知道问题是什么，但是如果我echo $userInfo->username;它没有显示任何东西。我得到了与数据库的连接。

函数userInfo（）：

    function userInfo(){    

    try {
        $stmt = $this->_db->prepare('SELECT * FROM members WHERE username = :username');
        $stmt->execute(array('username' => $_SESSION['username']));

        $row = $stmt->fetch(PDO::FETCH_OBJ);

        $username = $row->username;
        $firstname = $row->firstname;
        $lastname = $row->lastname;
        $worktitle = $row->worktitle;
        $email = $row->email;
        $admin = $row->admin;
        $address = $row->address;
        $city = $row->city;
        $zipcode = $row->zipcode;
        $phone = $row->phone;

      return array(
    'username'      => $username,
    'firstname'     => $firstname,
    'lastname'      => $lastname,
    'worktile'      => $worktitle,
    'email'         => $email,
    'admin'         => $admin,
    'address'       => $address,
    'city'          => $city,
    'zipcode'       => $zipcode,
    'phone'         => $phone
    );  

    } catch(PDOException $e) {
        echo '<p class="warning">'.$e->getMessage().'</p>';
    }
}

Answer 1

您的函数返回一个关联数组，但是从您的描述中，您将像对象一样访问返回值。

如果要像对象一样访问返回值，请编写如下函数：

function userInfo() {
    try {
        $stmt = $this->_db->prepare('SELECT * FROM members WHERE username = :username');
        $stmt->execute(array('username' => $_SESSION['username']));
        $row = $stmt->fetch(PDO::FETCH_OBJ);  // fetch as object
        return $row;
    } catch(PDOException $e) {
        echo '<p class="warning">'.$e->getMessage().'</p>';
    }
} 

$userInfo = userInfo();
echo $userInfo->username;  // object syntax

如果要像数组一样访问返回值，请编写如下函数：

function userInfo() {    
    try {
        $stmt = $this->_db->prepare('SELECT * FROM members WHERE username = :username');
        $stmt->execute(array('username' => $_SESSION['username']));
        $row = $stmt->fetch(PDO::FETCH_ASSOC);  // fetch as array
        return $row;    
    } catch(PDOException $e) {
        echo '<p class="warning">'.$e->getMessage().'</p>';
    }
} 

$userInfo = userInfo();
echo $userInfo["username"];  // associative array syntax

PHP函数userInfo不起作用

1 个答案: