Question

我正在尝试将带有文本和数字的数组转换为int。

数组separated：

分开[0]一些文字
分开[1] 1
分开[2]更多文字

我想要的是[1]最终成为一个int。

我试过了：

int logSetting = Integer.parseInt(String.valueOf(separated));

和

int logSetting = Integer.parseInt(String.valueOf(separated[1]));

两者都使应用程序崩溃

09-16 09:57:30.865: E/AndroidRuntime(27938): FATAL EXCEPTION: main

09-16 09:57:30.865: E/AndroidRuntime(27938): Process: my.project, PID: 27938
09-16 09:57:30.865: E/AndroidRuntime(27938): java.lang.NumberFormatException: Invalid int:

“[Ljava.lang.String; @ 42b273f0”

09-16 09:57:30.865: E/AndroidRuntime(27938):  at java.lang.Integer.invalidInt(Integer.java:137)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at java.lang.Integer.parse(Integer.java:374)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at java.lang.Integer.parseInt(Integer.java:365)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at java.lang.Integer.parseInt(Integer.java:331)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at my.project.MainActivity.fileReader(MainActivity.java:928)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at my.project.MainActivity.logCat(MainActivity.java:944)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at my.project.MainActivity$1.run(MainActivity.java:854)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at android.os.Handler.handleCallback(Handler.java:733)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at android.os.Handler.dispatchMessage(Handler.java:95)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at android.os.Looper.loop(Looper.java:157)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at android.app.ActivityThread.main(ActivityThread.java:5356)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at java.lang.reflect.Method.invokeNative(Native Method)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at java.lang.reflect.Method.invoke(Method.java:515)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1265)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1081)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at dalvik.system.NativeStart.main(Native Method)

Answer 1

你可以做这样的事情

String[] separated=new String[]{"some text ","1","some more text"};
int logSetting = 0;
  for(String i:separated){
     try {
        logSetting = Integer.parseInt(i);
      }catch (NumberFormatException e){
        System.out.println("NumberFormatException \""+i+"\" is not a number");
      }
     }
  System.out.println(logSetting);

Out put：

 NumberFormatException "some text " is not a number
 NumberFormatException "some more text" is not a number
 1

Answer 2

你快到了，int logSetting = Integer.parseInt(String.valueOf(separated[1]));应该是int logSetting = Integer.parseInt(separated[1]);。如果这不起作用，它可能会导致代码崩溃。你得到什么错误？

Answer 3

基于您的NumberFormatException异常，当您尝试将String转换为数字值时，如int，float，double，long等，其格式不正确

例如：

public class ConvertStringToNumber
{

  public static void main(String[] args)
  {
    try
    {
      String s = "FOOBAR";
      int i = Integer.parseInt(s); <--this line of code will never be reached
      System.out.println("int value = " + i);
    }
    catch (NumberFormatException nfe)
    {
      nfe.printStackTrace();
    }
  }

将字符串数组转换为int

3 个答案: