Question

如何仅使用索引删除字符串的一部分（如果索引处的字符存在于别处，则不使用正则表达式）？

我使用它，但它看起来非常令人沮丧!!

var str = "stringIwant to delete from";
var stringCodeLastIndex = str.length - 1;
var index2delete = 1;
var stringStart, stringEnd, finalString;

if (index2delete == 0) {
    stringStart = "";
} else {
    stringStart = str.substr(0, index2delete);
}
if (index2delete < stringCodeLastIndex) {
    stringEnd = str.substr(index2delete + 1);
} else {
    stringEnd = "";
}
finalString = stringStart + stringEnd;

Answer 1

substring非常聪明，可以自行处理无效索引：

＆＃13;

str = "someXXXstring";
del = 4;
len = 3
str = str.substring(0, del) + str.substring(del + len);
document.body.innerText += str + ","

str = "somestringXXX";
del = 10;
len = 20
str = str.substring(0, del) + str.substring(del + len);
document.body.innerText += str + ","

str = "somestring";
del = 0;
len = 200
str = str.substring(0, del) + str.substring(del + len);
document.body.innerText += str + ","

＆＃13;

Answer 2

在您的情况下，使用slice()更容易：

finalString = str.slice(0,index2delete)+str.slice(index2delete+1)

如果要删除更多字符，可以使用2个索引：

finalString = str.slice(0,start_index)+str.slice(endindex+1)

http://www.w3schools.com/jsref/jsref_slice_string.asp

Answer 3

从字符串中删除一个特定索引：

str.substr(0, indexToDelete) + str.substr(indexToDelete+1, str.length);

从字符串中删除一系列索引：

str.substr(0, startIndexToDelete) + str.substr(endIndexToDelete+1, str.length);

Answer 4

var str = "stringIwant to delete from";
var index2delete = 1;
arStr = str.split(""); // Making a JS Array of each characters
arStr.splice(index2delete,1); // Using array method to remove one entry at specified index
var finalString = arStr.join(''); // Convert Array to String

结果：

sringIwant to delete from

fiddle

Answer 5

然后创建一个子字符串并使用替换（＆＃39;您的子字符串＆＃39;，＆＃39;＆＃39;）它将用空格替换字符串的部分

按索引位置删除字符串的一部分

5 个答案: