我正在寻找一种方法来确定两个日期之间的差异。 正常的SQL DATEDIFF语句不会删除它，因为我需要排除非工作时间和天数，即特定周末和16:00 - 7:00之间的任何时间。
类似于excel中的NETWORKDAYS函数。
我正在编写Excel电子表格代码。使用VBA连接到SQL服务器来提取数据。
答案 0 :(得分：4)
这是我从网上下载并修改它以使用存储在访问表中的日期表的代码示例。我相信你可以再次改变它以指向工作表中的范围等，但基本的想法是一种享受
Option Compare Database
Option Explicit
Public Function dhCountWorkdaysA(ByVal dtmStart As Date, ByVal dtmEnd As Date, _
Optional adtmDates As Variant = Empty) _
As Integer
' Count the business days (not counting weekends/holidays) in
' a given date range.
' Modified from code in
' "Visual Basic Language Developer's Handbook"
' by Ken Getz and Mike Gilbert
' Copyright 2000; Sybex, Inc. All rights reserved.
' Requires:
' SkipHolidays
' CountHolidays
' IsWeekend
' In:
' dtmStart:
' Date specifying the start of the range (inclusive)
' dtmEnd:
' Date specifying the end of the range (inclusive)
' (dates will be swapped if out of order)
' adtmDates (Optional):
' Array containing holiday dates. Can also be a single
' date value.
' Out:
' Return Value:
' Number of working days (not counting weekends and optionally, holidays)
' in the specified range.
' Example:
' Debug.Print dhCountWorkdaysA(#7/2/2000#, #7/5/2000#, _
' Array(#1/1/2000#, #7/4/2000#))
'
' returns 2, because 7/2/2000 is Sunday, 7/4/2000 is a holiday,
' leaving 7/3 and 7/5 as workdays.
Dim intDays As Integer
Dim dtmTemp As Date
Dim intSubtract As Integer
' Swap the dates if necessary.>
If dtmEnd < dtmStart Then
dtmTemp = dtmStart
dtmStart = dtmEnd
dtmEnd = dtmTemp
End If
' Get the start and end dates to be weekdays.
dtmStart = SkipHolidaysA(adtmDates, dtmStart, 1)
dtmEnd = SkipHolidaysA(adtmDates, dtmEnd, -1)
If dtmStart > dtmEnd Then
' Sorry, no Workdays to be had. Just return 0.
dhCountWorkdaysA = 0
Else
intDays = dtmEnd - dtmStart + 1
' Subtract off weekend days. Do this by figuring out how
' many calendar weeks there are between the dates, and
' multiplying the difference by two (because there are two
' weekend days for each week). That is, if the difference
' is 0, the two days are in the same week. If the
' difference is 1, then we have two weekend days.
intSubtract = (DateDiff("ww", dtmStart, dtmEnd) * 2)
' The answer to our quest is all the weekdays, minus any
' holidays found in the table.
intSubtract = intSubtract + _
CountHolidaysA(adtmDates, dtmStart, dtmEnd)
dhCountWorkdaysA = intDays - intSubtract
End If
End Function
Private Function CountHolidaysA( _
adtmDates As Variant, _
dtmStart As Date, dtmEnd As Date) As Long
' Count holidays between two end dates.
'
' Modified from code in
' "Visual Basic Language Developer's Handbook"
' by Ken Getz and Mike Gilbert
' Copyright 2000; Sybex, Inc. All rights reserved.
' Required by:
' dhCountWorkdays
' Requires:
' IsWeekend
Dim lngItem As Long
Dim lngCount As Long
Dim blnFound As Long
Dim dtmTemp As Date
On Error GoTo HandleErr
lngCount = 0
Select Case VarType(adtmDates)
Case vbArray + vbDate, vbArray + vbVariant
' You got an array of variants, or of dates.
' Loop through, looking for non-weekend values
' between the two endpoints.
For lngItem = LBound(adtmDates) To UBound(adtmDates)
dtmTemp = adtmDates(lngItem)
If dtmTemp >= dtmStart And dtmTemp <= dtmEnd Then
If Not IsWeekend(dtmTemp) Then
lngCount = lngCount + 1
End If
End If
Next lngItem
Case vbDate
' You got one date. So see if it's a non-weekend
' date between the two endpoints.
If adtmDates >= dtmStart And adtmDates <= dtmEnd Then
If Not IsWeekend(adtmDates) Then
lngCount = 1
End If
End If
End Select
ExitHere:
CountHolidaysA = lngCount
Exit Function
HandleErr:
' No matter what the error, just
' return without complaining.
' The worst that could happen is that the code
' include a holiday as a real day, even if
' it's in the table.
Resume ExitHere
End Function
Public Function dhAddWorkDaysA(lngDays As Long, Optional dtmDate As Date = 0)
'Optional adtmDates As Variant) As Date
' Add the specified number of work days to the
' specified date.
' Modified from code in
' "Visual Basic Language Developer's Handbook"
' by Ken Getz and Mike Gilbert
' Copyright 2000; Sybex, Inc. All rights reserved.
' In:
' lngDays:
' Number of work days to add to the start date.
' dtmDate:
' date on which to start looking.
' Use the current date, if none was specified.
' adtmDates (Optional):
' Array containing holiday dates. Can also be a single
' date value, if that's what you want.
' Out:
' Return Value:
' The date of the working day lngDays from the start, taking
' into account weekends and holidays.
' Example:
' dhAddWorkDaysA(10, #2/9/2000#, Array(#2/16/2000#, #2/17/2000#))
' returns #2/25/2000#, which is the date 10 work days
' after 2/9/2000, if you treat 2/16 and 2/17 as holidays
' (just made-up holidays, for example purposes only).
' Did the caller pass in a date? If not, use
' the current date.
Dim lngCount As Long
Dim dtmTemp As Date
Dim adtmDates() As Variant
'loadup the adtmDates with all the records from the table tblNon_working_days
Dim db As DAO.Database
Dim rst As DAO.Recordset
Dim i As Long
Set rst = DBEngine(0)(0).OpenRecordset("tblNon_working_days", dbOpenSnapshot)
With rst
If .RecordCount > 0 Then
i = 1
.MoveFirst
Do Until .EOF
ReDim Preserve adtmDates(i)
adtmDates(i) = !Date
.MoveNext
i = i + 1
Loop
End If
End With
rst.Close
db.Close
Set rst = Nothing
Set db = Nothing
If dtmDate = 0 Then
dtmDate = Date
End If
dtmTemp = dtmDate
For lngCount = 1 To lngDays
dtmTemp = dhNextWorkdayA(dtmTemp, adtmDates)
Next lngCount
dhAddWorkDaysA = dtmTemp
End Function
Public Function dhNextWorkdayA( _
Optional dtmDate As Date = 0, _
Optional adtmDates As Variant = Empty) As Date
' Return the next working day after the specified date.
' Modified from code in
' "Visual Basic Language Developer's Handbook"
' by Ken Getz and Mike Gilbert
' Copyright 2000; Sybex, Inc. All rights reserved.
' Requires:
' SkipHolidays
' IsWeekend
' In:
' dtmDate:
' date on which to start looking.
' Use the current date, if none was specified.
' adtmDates (Optional):
' Array containing holiday dates. Can also be a single
' date value.
' Out:
' Return Value:
' The date of the next working day, taking
' into account weekends and holidays.
' Example:
' ' Find the next working date after 5/30/97
' dtmDate = dhNextWorkdayA(#5/23/1997#, #5/26/97#)
' ' dtmDate should be 5/27/97, because 5/26/97 is Memorial day.
' Did the caller pass in a date? If not, use
' the current date.
If dtmDate = 0 Then
dtmDate = Date
End If
dhNextWorkdayA = SkipHolidaysA(adtmDates, dtmDate + 1, 1)
End Function
Private Function SkipHolidaysA( _
adtmDates As Variant, _
dtmTemp As Date, intIncrement As Integer) As Date
' Skip weekend days, and holidays in the array referred to by adtmDates.
' Return dtmTemp + as many days as it takes to get to a day that's not
' a holiday or weekend.
' Modified from code in
' "Visual Basic Language Developer's Handbook"
' by Ken Getz and Mike Gilbert
' Copyright 2000; Sybex, Inc. All rights reserved.
' Required by:
' dhFirstWorkdayInMonthA
' dbLastWorkdayInMonthA
' dhNextWorkdayA
' dhPreviousWorkdayA
' dhCountWorkdaysA
' Requires:
' IsWeekend
Dim strCriteria As String
Dim strFieldName As String
Dim lngItem As Long
Dim blnFound As Boolean
On Error GoTo HandleErrors
' Move up to the first Monday/last Friday, if the first/last
' of the month was a weekend date. Then skip holidays.
' Repeat this entire process until you get to a weekday.
' Unless adtmDates an item for every day in the year (!)
' this should finally converge on a weekday.
Do
Do While IsWeekend(dtmTemp)
dtmTemp = dtmTemp + intIncrement
Loop
Select Case VarType(adtmDates)
Case vbArray + vbDate, vbArray + vbVariant
Do
blnFound = FindItemInArray(dtmTemp, adtmDates)
If blnFound Then
dtmTemp = dtmTemp + intIncrement
End If
Loop Until Not blnFound
Case vbDate
If dtmTemp = adtmDates Then
dtmTemp = dtmTemp + intIncrement
End If
End Select
Loop Until Not IsWeekend(dtmTemp)
ExitHere:
SkipHolidaysA = dtmTemp
Exit Function
HandleErrors:
' No matter what the error, just
' return without complaining.
' The worst that could happen is that we
' include a holiday as a real day, even if
' it's in the array.
Resume ExitHere
End Function
Private Function IsWeekend(dtmTemp As Variant) As Boolean
' If your weekends aren't Saturday (day 7) and Sunday (day 1),
' change this routine to return True for whatever days
' you DO treat as weekend days.
' Modified from code in "Visual Basic Language Developer's Handbook"
' by Ken Getz and Mike Gilbert
' Copyright 2000; Sybex, Inc. All rights reserved.
' Required by:
' SkipHolidays
' dhFirstWorkdayInMonth
' dbLastWorkdayInMonth
' dhNextWorkday
' dhPreviousWorkday
' dhCountWorkdays
If VarType(dtmTemp) = vbDate Then
Select Case WeekDay(dtmTemp)
Case vbSaturday, vbSunday
IsWeekend = True
Case Else
IsWeekend = False
End Select
End If
End Function
Private Function FindItemInArray(varItemToFind As Variant, _
avarItemsToSearch As Variant) As Boolean
Dim lngItem As Long
On Error GoTo HandleErrors
For lngItem = LBound(avarItemsToSearch) To UBound(avarItemsToSearch)
If avarItemsToSearch(lngItem) = varItemToFind Then
FindItemInArray = True
GoTo ExitHere
End If
Next lngItem
ExitHere:
Exit Function
HandleErrors:
' Do nothing at all.
' Return False.
Resume ExitHere
End Function