以下是我正在使用的示例多列表。现在我需要找到给定值的indices
,如果它出现在列表中的任何位置。例如:对于lis[0][2][2][1][0] which is 'span 1 2'
,我想将索引设为[0,2,2,1,0]
。
lis = [['Root', ['span 1 6'], ['Nucleus', ['span 1 3'], ['Nucleus', ['span 1 2'], ['Nucleus', ['leaf 1'], ['text', "Specific knowledge "]], ['Satellite', ['leaf 2'], ['rel2par Elaboration'], ['text', 'required !_']]], ['Satellite', ['leaf 3'], ['rel2par Elaboration'], ['text', 'The tester is ']]], ['Satellite', ['span 4 6'], ['rel2par Elaboration'], ['Satellite', ['leaf 4'], ['rel2par Attribution'], ['text', 'For instance , the tester is aware!_']], ['Nucleus', ['span 5 6'], ['Nucleus', ['leaf 5'], ['rel2par Contrast'], ['text', 'that a!_']], ['Nucleus', ['leaf 6'], ['rel2par Contrast'], ['text', 'but ']]]]]]
我尝试了以下内容(从网络源修改)。
from copy import copy
def scope2(word, list, indexes = None):
flag = 0
result = []
if not indexes:
indexes = []
for index, item in enumerate(list):
try:
current_index = indexes + [index]
result.append(current_index + [item.index(word)])
except ValueError:
pass
print item
print str(current_index) + ":::::" + str(list.index(item))
for stuff in item:
if type(stuff) == type([]):
flag =1
if flag==1:
indexes.append(index)
result.extend(scope2(word, item, copy(indexes)))
return result
这里的问题是兄弟的索引(同一级别的列表)也会被返回,但并不总是如此。一些示例输出类似于
for 0,2,3,1 it returns 0,2,3,1,0, similarly for lis[0][2][3][4][3][3] it returns 0,2,3,3,4,3,3
等等。可能出现什么问题?
答案 0 :(得分:2)
>>> def trail(word, lst):
... if word in lst:
... return [lst.index(word)]
... for i, x in enumerate(lst):
... if not isinstance(x, list):
... continue
... ret = trail(word, x)
... if ret is not None:
... return [i] + ret
...
>>> trail('span 1 2', lis)
[0, 2, 2, 1, 0]
>>> lis[0][2][2][1][0]
'span 1 2'
>>> trail('no such string', lis)
>>>
答案 1 :(得分:1)
这是深度优先和广度优先搜索的实现,不仅限于字符串。需要稍微改造才能搜索列表或元组。
>>> l = [['Root', ['span 1 6'], ['Nucleus', ['span 1 3'], ['Nucleus', ['span 1 2'], ['Nucleus', ['leaf 1'], ['text', "Specific knowledge "]], ['Satellite', ['leaf 2'], ['rel2par Elaboration'], ['text', 'required !_']]], ['Satellite', ['leaf 3'], ['rel2par Elaboration'], ['text', 'The tester is ']]], ['Satellite', ['span 4 6'], ['rel2par Elaboration'], ['Satellite', ['leaf 4'], ['rel2par Attribution'], ['text', 'For instance , the tester is aware!_']], ['Nucleus', ['span 5 6'], ['Nucleus', ['leaf 5'], ['rel2par Contrast'], ['text', 'that a!_']], ['Nucleus', ['leaf 6'], ['rel2par Contrast'], ['text', 'but ']]]]]]
>>> def depth_first(term,data):
... for i, item in enumerate(data):
... if isinstance(item,Sequence) and not isinstance(item,basestring):
... r = depth_first(term,item)
... if not r is None:
... return [i] + r
... else:
... if item == term:
... return [i]
...
>>> def breadth_first(term,data):
... later = []
... for i, item in enumerate(data):
... if isinstance(item,Sequence) and not isinstance(item,basestring):
... later.append((i,item))
... else:
... if item == term:
... return [i]
... for i, item in later:
... r = breadth_first(term,item)
... if not r is None:
... return [i] + r
>>> depth_first('span 1 2',l)
[0, 2, 2, 1, 0]
>>> breadth_first('span 1 2',l)
[0, 2, 2, 1, 0]