（*）更新了扩展名

Question

我有一个带有Azure后端的IOS应用，并希望记录某些事件，例如登录以及正在运行的应用用户的哪个版本。

如何使用Swift返回版本号和内部版本号？

Answer 1

修改

针对Swift 4.2进行了更新

let appVersion = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String

修改

正如@azdev在Xcode的新版本中指出的那样，你会在尝试我之前的解决方案时遇到编译错误，要解决这个问题，只需按照建议进行编辑就可以使用！来打开捆绑字典！

let nsObject: AnyObject? = NSBundle.mainBundle().infoDictionary!["CFBundleShortVersionString"]

结束修改

只需使用与Objective-C相同的逻辑，但需要进行一些小的更改

//First get the nsObject by defining as an optional anyObject let nsObject: AnyObject? = NSBundle.mainBundle().infoDictionary["CFBundleShortVersionString"] //Then just cast the object as a String, but be careful, you may want to double check for nil let version = nsObject as String

我希望这可以帮助你。

大卫

Answer 2

我知道这已经得到了回答，但我个人认为这有点清洁：

Swift 3.0：

 if let version = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String {
    self.labelVersion.text = version
}

Swift＆lt; 2.3

if let version = NSBundle.mainBundle().infoDictionary?["CFBundleShortVersionString"] as? String {
    self.labelVersion.text = version
}

这样，if let版本负责条件处理（在我的情况下设置标签文本），如果infoDictionary或CFBundleShortVersionString为nil，则可选的解包将导致代码被跳过。

Answer 3

针对Swift 3.0进行了更新

NS - 前缀现在已经在Swift 3.0中消失，并且一些属性/方法已将名称更改为更加Swifty。以下是现在的情况：

extension Bundle {
    var releaseVersionNumber: String? {
        return infoDictionary?["CFBundleShortVersionString"] as? String
    }
    var buildVersionNumber: String? {
        return infoDictionary?["CFBundleVersion"] as? String
    }
}

Bundle.main.releaseVersionNumber
Bundle.main.buildVersionNumber

旧更新的答案

自从我的原始答案以来，我一直在使用Frameworks，所以我我希望将我的解决方案更新为更简单的东西在多捆绑环境中更有用：
extension NSBundle {

    var releaseVersionNumber: String? {
        return self.infoDictionary?["CFBundleShortVersionString"] as? String
    }

    var buildVersionNumber: String? {
        return self.infoDictionary?["CFBundleVersion"] as? String
    }

}
现在，此扩展程序将在应用程序中用于识别主要内容捆绑包和任何其他包含的捆绑包（例如共享框架）扩展程序设计或第三个框架，如AFNetworking），如下所示：
NSBundle.mainBundle().releaseVersionNumber
NSBundle.mainBundle().buildVersionNumber

// or...

NSBundle(URL: someURL)?.releaseVersionNumber
NSBundle(URL: someURL)?.buildVersionNumber

原始答案

我想改进一些已发布的答案。我写了一篇   类扩展，可以添加到您的工具链中以处理此问题   更合乎逻辑的方式。
extension NSBundle {

class var applicationVersionNumber: String {
    if let version = NSBundle.mainBundle().infoDictionary?["CFBundleShortVersionString"]
为？字符串{ 返回版本 } 返回“版本号不可用” }
class var applicationBuildNumber: String {
    if let build = NSBundle.mainBundle().infoDictionary?["CFBundleVersion"] as? String {
        return build
    }
    return "Build Number Not Available"
}

}
现在您可以通过以下方式轻松访问：
let versionNumber = NSBundle.applicationVersionNumber

Answer 4

我也知道这已经得到了解答，但我结束了以前的答案：

（*）更新了扩展名

extension Bundle {
    var releaseVersionNumber: String? {
        return infoDictionary?["CFBundleShortVersionString"] as? String
    }
    var buildVersionNumber: String? {
        return infoDictionary?["CFBundleVersion"] as? String
    }
    var releaseVersionNumberPretty: String {
        return "v\(releaseVersionNumber ?? "1.0.0")"
    }
}

用法：

someLabel.text = Bundle.main.releaseVersionNumberPretty

@Deprecated：旧答案

Swift 3.1 ：

class func getVersion() -> String {
    guard let version = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String else {
        return "no version info"
    }
    return version
}

旧版本：

class func getVersion() -> String {
    if let version = NSBundle.mainBundle().infoDictionary?["CFBundleShortVersionString"] as? String {
        return version
    }
    return "no version info"
}

因此，如果您想设置标签文本或想要在其他地方使用;

self.labelVersion.text = getVersion()

Answer 5

Swift 4.0

let version = Bundle.main.infoDictionary!["CFBundleShortVersionString"]!
let build = Bundle.main.infoDictionary!["CFBundleVersion"]!

Answer 6

我在Bundle上做了一个扩展

extension Bundle {

    var appName: String {
        return infoDictionary?["CFBundleName"] as! String
    }

    var bundleId: String {
        return bundleIdentifier!
    }

    var versionNumber: String {
        return infoDictionary?["CFBundleShortVersionString"] as! String 
    }

    var buildNumber: String {
        return infoDictionary?["CFBundleVersion"] as! String
    }

}

然后使用它

versionLabel.text = "\(Bundle.main.appName) v \(Bundle.main.versionNumber) (Build \(Bundle.main.buildNumber))"

Answer 7

对于Swift 3.0，NSBundle无法正常工作，以下代码可以正常运行。

let versionNumberString =
      Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString")
          as! String

仅对于内部版本号，它是：

let buildNumberString =
      Bundle.main.object(forInfoDictionaryKey: "CFBundleVersion")
          as! String

令人困惑的CFBundleVersion＆＃39;是在X轴上输入的构建编号，在General-＆gt; Identity。

Answer 8

Xcode 9.4.1 Swift 4.1

请注意使用localizedInfoDictionary来选择捆绑显示名称的正确语言版本。

Listbox

Answer 9

Xcode 8，Swift 3：

let gAppVersion = Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString") ?? "0"
let gAppBuild = Bundle.main.object(forInfoDictionaryKey: "CFBundleVersion") ?? "0"

Answer 10

将5作为UIApplication扩展

extension UIApplication {
    static var release: String {
        return Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString") as! String? ?? "x.x"
    }
    static var build: String {
        return Bundle.main.object(forInfoDictionaryKey: "CFBundleVersion") as! String? ?? "x"
    }
    static var version: String {
        return "\(release).\(build)"
    }
}

示例用法：

print("release: \(UIApplication.release)")
print("build: \(UIApplication.build)")
print("version: \(UIApplication.version)")

Answer 11

我的回答（截至2015年8月），鉴于Swift不断发展：

let version = NSBundle.mainBundle().infoDictionary!["CFBundleVersion"] as! String

Answer 12

Bundle + Extension.swift（SwiftUI，Swift 5，Xcode 11）

我结合了一些答案中的想法，并进行了扩展：

一个SwiftUI示例
如果Info.plist中缺少键，则显示警告三角图释（而不是使应用程序崩溃）

导入基金会

extension Bundle {
    
    public var appVersionShort: String? {
        if let result = infoDictionary?["CFBundleShortVersionString"] as? String {
            return result
        } else {
            return "⚠️"
        }
    }
    public var appVersionLong: String? {
        if let result = infoDictionary?["CFBundleVersion"] as? String {
            return result
        } else {
            return "⚠️"
        }
    }
    public var appName: String? {
        if let result = infoDictionary?["CFBundleName"] as? String {
            return result
        } else {
            return "⚠️"
        }
    }
}

SwiftUI示例使用

VStack {

     Text("Version: \(Bundle.main.appVersionShort!) (\(Bundle.main.appVersionLong!))")
                    .font(.subheadline)
                    .frame(maxWidth: .infinity, maxHeight: .infinity)
}

Answer 13

Swift 4，适用于捆绑软件的扩展程序

import Foundation

public extension Bundle {

    public var shortVersion: String {
        if let result = infoDictionary?["CFBundleShortVersionString"] as? String {
            return result
        } else {
            assert(false)
            return ""
        }
    }

    public var buildVersion: String {
        if let result = infoDictionary?["CFBundleVersion"] as? String {
            return result
        } else {
            assert(false)
            return ""
        }
    }

    public var fullVersion: String {
        return "\(shortVersion)(\(buildVersion))"
    }
}

Answer 14

看过文档后，我相信以下内容更清晰：

let version = 
NSBundle.mainBundle().objectForInfoDictionaryKey("CFBundleShortVersionString") 
as? String

Source：＆＃34;使用此方法优于其他访问方法，因为它在有一个可用时返回键的本地化值。＆＃34;

Answer 15

Bundle + Extensions.swift

import Foundation

extension Bundle {
    var versionNumber: String? {
        return infoDictionary?["CFBundleShortVersionString"] as? String
    }

    var buildNumber: String? {
        return infoDictionary?["CFBundleVersion"] as? String
    }

    var bundleName: String? {
        return infoDictionary?["CFBundleName"] as? String
    }
}

用法：

someLabel.text = Bundle.main.versionNumber

Answer 16

对于Swift 1.2来说：

@interface ViewController ()

@property (weak, nonatomic) IBOutlet UIView *redView;

@property (strong, nonatomic) UITextField *textField;

@property (strong, nonatomic) UITapGestureRecognizer *gesture;

@end

@implementation ViewController

- (void)viewDidLoad
{
    [super viewDidLoad];

    self.textField                 = [[UITextField alloc] initWithFrame:CGRectMake(0.f, 0.f, self.redView.frame.size.width, 30.f)];
    self.textField.backgroundColor = [UIColor lightGrayColor];

    [self.redView addSubview:self.textField];

    self.gesture = [[UITapGestureRecognizer alloc] initWithTarget:self
                                                           action:@selector(animateRedView:)];

    [self.view addGestureRecognizer:self.gesture];
}

- (IBAction)animateRedView:(id)sender
{
    [UIView animateWithDuration:.5
                          delay:0
         usingSpringWithDamping:1.2
          initialSpringVelocity:5
                        options:0
                     animations:^{

                         CGRect redViewFrame = self.redView.frame;

                         [self.redView setFrame:CGRectMake((self.view.frame.size.width - redViewFrame.size.width),
                                                           redViewFrame.origin.y,
                                                           redViewFrame.size.width,
                                                           redViewFrame.size.height)];

                     } completion:^(BOOL finished) {

                         [self.textField becomeFirstResponder];

                     }];
}

@end

Answer 17

斯威夫特3：

版本号

if let versionNumberString = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String { // do something }

内部版本号

if let buildNumberString = Bundle.main.infoDictionary?["CFBundleVersion"] as? String { // do something }

Answer 18

Swift 4

ref

Bundle.main.infoDictionary！[＆＃34; CFBundleShortVersionString＆＃34;]

Swift旧语法

func getAppVersion() -> String {
    return "\(Bundle.main.infoDictionary!["CFBundleShortVersionString"] ?? "")"
}

Answer 19

对于 Swift 5 ：

func getAppCurrentVersionNumber() -> String {
    let nsObject: AnyObject? = Bundle.main.infoDictionary!["CFBundleShortVersionString"] as AnyObject?
    return nsObject as! String
}

Answer 20

public var appVersionNumberString: String {
get {
    return Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString") as! String
}
}

Answer 21

extension UIApplication {

    static var appVersion: String {
        if let appVersion = NSBundle.mainBundle().objectForInfoDictionaryKey("CFBundleShortVersionString") {
            return "\(appVersion)"
        } else {
            return ""
        }
    }

    static var build: String {
        if let buildVersion = NSBundle.mainBundle().objectForInfoDictionaryKey(kCFBundleVersionKey as String) {
            return "\(buildVersion)"
        } else {
            return ""
        }
    }

    static var versionBuild: String {
        let version = UIApplication.appVersion
        let build = UIApplication.build

        var versionAndBuild = "v\(version)"

        if version != build {
            versionAndBuild = "v\(version)(\(build))"
        }

        return versionAndBuild
    }

}

注意：如果你没有设置app版本或版本，你应该使用if here，如果你试图使用它会导致崩溃！打开包装。

Answer 22

对于感兴趣的任何人，github都提供了一个名为SwifterSwift的漂亮且整洁的库，并且针对每个版本的swift也提供了完整的文档（请参见swifterswift.com）。

使用此库，读取应用程序版本和内部版本号将像这样简单：

import SwifterSwift

let buildNumber = SwifterSwift.appBuild
let version = SwifterSwift.appVersion

Answer 23

SWIFT 4

//首先通过定义为可选的AnyObject

来获取nsObject

let nsObject: AnyObject? = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as AnyObject

//然后将对象强制转换为String，但要小心，你可能需要仔细检查nil

let version = nsObject as! String

Answer 24

这是Swift 3.2的更新版本：

extension UIApplication
{
    static var appVersion:String
    {
        if let appVersion = Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString")
        {
            return "\(appVersion)"
        }
        return ""
    }

    static var buildNumber:String
    {
        if let buildNum = Bundle.main.object(forInfoDictionaryKey: kCFBundleVersionKey as String)
        {
            return "\(buildNum)"
        }
        return ""
    }

    static var versionString:String
    {
        return "\(appVersion).\(buildNumber)"
    }
}

Answer 25

if let version = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String {
            self.lblAppVersionValue.text = version
        }

Answer 26

我为UIApplication创建了扩展。

extension UIApplication {
    static var appVersion: String {
        let versionNumber = Bundle.main.infoDictionary?[IdentifierConstants.InfoPlist.versionNumber] as? String
        let buildNumber = Bundle.main.infoDictionary?[IdentifierConstants.InfoPlist.buildNumber] as? String

        let formattedBuildNumber = buildNumber.map {
            return "(\($0))"
        }

        return [versionNumber,formattedBuildNumber].compactMap { $0 }.joined(separator: " ")
    }
}

struct IdentifierConstants {
    struct InfoPlist {
        static let versionNumber = "CFBundleShortVersionString"
        static let buildNumber = "CFBundleVersion"
    }
}

Answer 27

Swift 5.3

let infoDictionaryKey = kCFBundleVersionKey as String
guard let currentVersion = Bundle.main.object(forInfoDictionaryKey: infoDictionaryKey) as? String
else { fatalError("Expected to find a bundle version in the info dictionary") }

Answer 28

简单的实用程序功能可将应用程序版本返回为 Int

func getAppVersion() -> Int {

        if let appVersion = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String {

            let appVersionClean = appVersion.replacingOccurrences(of: ".", with: "", options: NSString.CompareOptions.literal, range:nil)

            if let appVersionNum = Int(appVersionClean) {
                return appVersionNum
            }
        }
        return 0
    }

Answer 29

OP要求提供版本号和内部版本号。不幸的是，大多数答案都没有提供这两个选项。此外，其他人添加了不必要的扩展方法。这很简单，可以解决OP的问题：

// Example output: "1.0 (234)"
private func versionAndBuildNumber() -> String {
  let versionNumber = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String
  let buildNumber = Bundle.main.infoDictionary?["CFBundleVersion"] as? String
  if let versionNumber = versionNumber, let buildNumber = buildNumber {
    return "\(versionNumber) (\(buildNumber))"
  } else if let versionNumber = versionNumber {
    return versionNumber
  } else if let buildNumber = buildNumber {
    return buildNumber
  } else {
    return ""
  }
}

Answer 30

您现在可以为此使用常量，而不必像以前一样使用字符串类型的代码，这使事情变得更加方便。

var appVersion: String {
    return Bundle.main.infoDictionary![kCFBundleVersionKey as String] as! String
}

Answer 31

Swift 5更新

这是我用来确定是否显示“应用程序已更新”页面的功能。它返回内部版本号，我正在将其转换为Int：

if let version: String = Bundle.main.infoDictionary?["CFBundleVersion"] as? String {
        guard let intVersion = Int(version) else { return }

        if UserDefaults.standard.integer(forKey: "lastVersion") < intVersion {
            print("need to show popup")
        } else {
            print("Don't need to show popup")
        }

        UserDefaults.standard.set(intVersion, forKey: "lastVersion")
    }

如果以前从未使用过，它将返回比当前内部版本号低的0。要不向新用户显示此屏幕，只需在首次登录后或入职完成后添加内部版本号即可。

Answer 32

if let version = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String {
        lblVersion.text = "Version \(version)"

    }

Answer 33

对于 Swift 5.0 ：

let appVersion = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as! String

Answer 34

Swift 2.0

//First get the nsObject by defining as an optional anyObject

let nsObject: AnyObject? = NSBundle.mainBundle().infoDictionary!["CFBundleShortVersionString"]
let version = nsObject as! String

如何使用Swift获取App版本和内部版本号？

34 个答案:

（*）更新了扩展名

@Deprecated：旧答案

Swift 5更新