我怎样才能解决ArrayIndexOutOfBoundsException - android

时间:2014-09-22 13:25:23

标签: android

public class MainActivity extends ActionBarActivity {
    Context context;
    private String[] myString;
    private static final Random rgenerator = new Random();
    private AdView adView;
    int index = 0;
    private static final String AD_UNIT_ID = "ca-app-pub-7628432187347131/3277094808";

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        getSupportActionBar().hide();
        // Create an ad.
        adView = new AdView(this);
        adView.setAdSize(AdSize.SMART_BANNER);
        adView.setAdUnitId(AD_UNIT_ID);

        context = this;
        LinearLayout layout = (LinearLayout) findViewById(R.id.ads_lin);
        layout.addView(adView);

        AdRequest adRequest = new AdRequest.Builder()
                .addTestDevice(AdRequest.DEVICE_ID_EMULATOR)
                .addTestDevice("5B895A3CC0CA50D56506E300A4C8342B")
                .addTestDevice("D039292A1F434C999B21503D63D6FD88")

                .addTestDevice("TEST_EMULATOR").build();

        // Start loading the ad in the background.

        adView.loadAd(adRequest);
        // Start loading the ad in the background.
        final TextView tv = (TextView) findViewById(R.id.quote);

        Resources res = getResources();
        myString = res.getStringArray(R.array.quote);
        final String q = myString[rgenerator.nextInt(myString.length)];
        tv.setText(q);
        Button btn = (Button) findViewById(R.id.btn);
        Button btnNext = (Button) findViewById(R.id.btnNext);
        Button btnPreview = (Button) findViewById(R.id.btnPreview);
        btn.setOnClickListener(new View.OnClickListener() {

            public void onClick(View v) {
                myString = getResources().getStringArray(R.array.quote);
                index = rgenerator.nextInt(myString.length);
                String q = myString[index];
                tv.setText(q);
            }
        });

        btnNext.setOnClickListener(new View.OnClickListener() {
            public void onClick(View v) {
                String q = myString[index++];
                tv.setText(q);
            }
        });

        btnPreview.setOnClickListener(new View.OnClickListener(){
            public void onClick(View v){
                String q = myString[index--];
                        tv.setText(q);
            }
        });
    }

    @Override
    public void onResume() {
        super.onResume();
        if (adView != null) {
            adView.resume();
        }
    }

    @Override
    public void onPause() {
        if (adView != null) {
            adView.pause();
        }
        super.onPause();
    }

    /** Called before the activity is destroyed. */
    @Override
    public void onDestroy() {
        // Destroy the AdView.
        if (adView != null) {
            adView.destroy();
        }
        super.onDestroy();
    }

}

我不知道如何解决这个错误,我是android开发的初学者,我不知道如何编写代码来解决这个问题。 我在互联网上看了一个小时,但我没有找到帮助我的东西。 这里LOGCAT:

09-22 13:05:43.838: E/dalvikvm(26277): adjustAdaptiveCoef max=4194304, min=1048576, ut=568
09-22 13:06:06.510: E/AndroidRuntime(26277): FATAL EXCEPTION: main
09-22 13:06:06.510: E/AndroidRuntime(26277): java.lang.ArrayIndexOutOfBoundsException: length=670; index=-1
09-22 13:06:06.510: E/AndroidRuntime(26277):    at com.example.stiaica.MainActivity$3.onClick(MainActivity.java:80)
09-22 13:06:06.510: E/AndroidRuntime(26277):    at android.view.View.performClick(View.java:4432)
09-22 13:06:06.510: E/AndroidRuntime(26277):    at android.view.View$PerformClick.run(View.java:18338)
09-22 13:06:06.510: E/AndroidRuntime(26277):    at android.os.Handler.handleCallback(Handler.java:725)
09-22 13:06:06.510: E/AndroidRuntime(26277):    at android.os.Handler.dispatchMessage(Handler.java:92)
09-22 13:06:06.510: E/AndroidRuntime(26277):    at android.os.Looper.loop(Looper.java:137)
09-22 13:06:06.510: E/AndroidRuntime(26277):    at android.app.ActivityThread.main(ActivityThread.java:5283)
09-22 13:06:06.510: E/AndroidRuntime(26277):    at java.lang.reflect.Method.invokeNative(Native Method)
09-22 13:06:06.510: E/AndroidRuntime(26277):    at java.lang.reflect.Method.invoke(Method.java:511)
09-22 13:06:06.510: E/AndroidRuntime(26277):    at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1102)
09-22 13:06:06.510: E/AndroidRuntime(26277):    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:869)

有人可以帮我处理代码吗?谢谢     09-22 13:06:06.510:E / AndroidRuntime(26277):at dalvik.system.NativeStart.main(Native Method)

1 个答案:

答案 0 :(得分:1)

如果您搜索过,则搜索不够。

问题基本上就是这一行:String q = myString[index--];

如果变量index小于0,则会发生异常。因此,您尝试访问不存在的负值,因此会抛出异常。

您可以尝试一些事项:

  • 检查变量index是否大于0
  • 如果它不大于0:将其设置为0或者可以将其设置为数组的最后一个点(例如,如果数组的大小为10,则可以将其设置为索引9 ,所以你在整个阵列中都有一个连续循环
  • 或者你不能低于0。

第一个是负面的,第二个是正面的:

if(index < 0)
{ 
    index = myString.length - 1;
}

if(index >= myString.length)
{ 
    index = 0;
}
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