SQL:如何使用表加入视图?

时间:2010-04-08 14:16:04

标签: mysql sql join views

更新:

我使用MySQL语句创建视图:

如果出版了50多本书,我需要出示编辑名,姓和城。我有三张桌子:

create table editors (
 ed_id  char(11),
 ed_lname varchar(20),
  ed_fname varchar(20),
  ed_pos  varchar(12),
  phone  varchar(10),
  address  varchar(30),
  city  varchar(20),
  state  char(2),
  zip  char(5),
  ed_boss  char(11));

create table titleditors (
 ed_id  char(11),
 title_id char(6),
 ed_ord  integer);

create table salesdetails (
 sonum  integer,
 qty_ordered integer,
 qty_shipped integer,
 title_id char(6),
 date_shipped date);

有谁能告诉我创建此结果的代码是什么? 我没有制作表格,我只需要处理我给出的内容。

2 个答案:

答案 0 :(得分:18)

过时的语法(注意连接条件和过滤条件的混合):

CREATE VIEW qtyorderedview AS
  SELECT 
     salesdetails.title_id, salesdetails.qty_shipped,
     editors.ed_id, editors.ed_lname, editors.ed_fname, editors.city
  FROM
     titleditors, salesdetails, editors 
  WHERE
     titleditors.title_id = salesdetails.title_id
     AND editors.ed_id = titleditors.ed_id
     AND salesdetails.qty_ordered > 50

现代语法(连接条件和过滤条件是分开的):

CREATE VIEW qtyorderedview AS
  SELECT 
     salesdetails.title_id, salesdetails.qty_shipped,
     editors.ed_id, editors.ed_lname, editors.ed_fname, editors.city
  FROM
     titleditors
     INNER JOIN salesdetails ON titleditors.title_id = salesdetails.title_id
     INNER JOIN editors      ON editors.ed_id = titleditors.ed_id
  WHERE
     salesdetails.qty_ordered > 50

加入反对视图的工作方式与对表的连接完全相同。只需使用视图名称代替常规表名。

答案 1 :(得分:5)

SELECT  e.*
FROM    (
        SELECT  DISTINCT te.ed_id
        FROM    (
                SELECT  title_id
                FROM    sales_details
                GROUP BY
                        title_id
                HAVING  SUM(qty_shipped) > 50
                ) t
        JOIN    titleditors te
        ON      te.title_id = t.title_id
        ) te
JOIN    editors e
ON      e.ed_id = te.ed_id
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