Question

pyg = 'ay'

original = raw_input('Enter a word:')

if len(original) > 0 and original.isalpha():
    print original    
    word = original.lower()
    first = word[0]
    second = word[1]
    new_word = word + first + pyg  
    new_word = new_word[1:len(new_word)]
    print new_word
else:
    print 'empty'

我需要这个循环，并且当用户使用低位或大写字母的任意组合输入“退出”时。（qUit，QUIT，quIT，即。）

任何提示都表示赞赏。感谢。

Answer 1

尝试这样的事情：

pyg = 'ay'
original = raw_input('Enter a word:')

while original and original.strip().upper() != 'QUIT':
    # loop body
    if len(original) > 0 and original.isalpha():
        print original    
        word = original.lower()
        first = word[0]
        second = word[1]
        new_word = word + first + pyg  
        new_word = new_word[1:len(new_word)]
        print new_word
    else:
        print 'empty'
    # read again, for next loop
    original = raw_input('Enter a word:')

Answer 2

试试这个

pyg = 'ay'

while True:

    original = raw_input('Enter a word:')

    if original.upper() == 'QUIT':
        break

    if len(original) > 0 and original.isalpha():
        print original    
        word = original.lower()
        first = word[0]
        second = word[1]
        new_word = word + first + pyg  
        new_word = new_word[1:len(new_word)]
        print new_word
    else:
        print 'empty'
        break

Answer 3

new_word = new_word [1：]

##它更好！ #to拆分第一个单词

nom ='AlassaneAli'

mylist = list（）

代表我的名字：

    mylist.append(i)

对于范围内（len（mylist））：

print(mylist[a])

print（mylist [1：]）

在python中循环这个程序的最佳方法是什么？

3 个答案: