Question

我有2个数组。我想合并它们。

数组1：

Array
(
[100] => 
[50] => 
[CREDIT] => 14.31
[CHEQUE] => 
)

数组2：

Array
(
[0] => Array
    (
        [id] => 501
    )
[1] => Array
    (
        [id] => 502
    )
[2] => Array
    (
        [id] => 503
    )

我将这些结果与$array1+$array2合并后得到此结果：

Array
(
[100] => 
[50] => 
[CREDIT] => 14.31
[CHEQUE] => 
[0] => Array
    (
        [id] => 501
    )
)

我的预期结果是：

Array
(
[100] => 
[50] => 
[CREDIT] => 14.31
[CHEQUE] => 
[0] => Array
    (
    [0] => Array
        (
            [id] => 501
        )
    [1] => Array
        (
            [id] => 502
        )
    [2] => Array
        (
            [id] => 503
        )
    )
)

可能是什么原因？感谢。

Answer 1

在您的具体案例中，正如$ Sadiq所提到的，我只会做$array1[0] = $array2。

$arr1 = [
    '100' => '',
    '50' => '',
    'CREDIT' => 14.31,
    'CHEQUE' => ''
];

$arr2 = [
    '0' => [
        'id' => 501
    ],
    '1' => [
        'id' => 502
    ],
    '2' => [
        'id' => 503
    ],
];

$arr1[0] = $arr2;
print_r($arr1);

<强>输出

Array
(
    [100] => 
    [50] => 
    [CREDIT] => 14.31
    [CHEQUE] => 
    [0] => Array
        (
            [0] => Array
                (
                    [id] => 501
                )

            [1] => Array
                (
                    [id] => 502
                )

            [2] => Array
                (
                    [id] => 503
                )

        )

)

Answer 2

$arr1= array(100=>'',50=>'','CREDIT'=>14.31,'CHEQUE'=>'');
print_r($arr1);

$arr2  = array(0 => array('id' => 501),1 => array ( 'id' => 502),2 => array('id'=> 503));
print_r($arr2);

$result = $arr1 + array($arr2);
print_r($result);

结果：

Array
    (
        [100] => 
        [50] => 
        [CREDIT] => 14.31
        [CHEQUE] => 
    )

    Array
    (
        [0] => Array
            (
                [id] => 501
            )

        [1] => Array
            (
                [id] => 502
            )

        [2] => Array
            (
                [id] => 503
            )

    )

    Array
    (
        [100] => 
        [50] => 
        [CREDIT] => 14.31
        [CHEQUE] => 
        [0] => Array
            (
                [0] => Array
                    (
                        [id] => 501
                    )

                [1] => Array
                    (
                        [id] => 502
                    )

                [2] => Array
                    (
                        [id] => 503
                    )

            )

    )

Answer 3

这些将适用于您需要的任意数量的阵列以及所需的维数。

对于这些函数，将最高优先级数组设置为最低索引：

function overlapArrays($array) {
    if(count($array) > 1) {
        for($i = (count($array) - 1);$i >= 0;$i--) {
            if(($i - 1) >= 0) {
                prioritize($array[$i], $array[$i - 1]);
            }
            else {
                break;
            }
        }
        return $array[0];
    }
    else {
        return $array;
    }
}

function prioritize($arr1, &$arr2) {
    foreach($arr1 as $key => $value) {
        if(!array_key_exists($key, $arr2)) {
            $arr2[$key] = $value;
        }
        elseif(is_array($value) && is_array($arr2[$key])) {
            prioritize($value, $arr2[$key]);
        }
    }
}

$array1 = [
    100 => '',
    50 => '',
    'CREDIT' => 14.31,
    'CHEQUE' => ''
];

$array2 = [
    0 => [
        'id' => 501
    ],
    1 => [
        'id' => 502
    ],
    2 => [
        'id' => 503
    ]
];

$merger = Array($array1, $array2);

$results = overlapArrays($merger);

例如，如果要将第一个数组和第二个数组中存在的键保留在第一个数组中，则将第一个数组分配给合并数组中的0索引。如果希望array2在匹配时保留值，则将array2分配给0索引。

$array1 = Array(
    'one' => Array(
         'two' => 2,
         'three' => 3
    )
);
$array2 = Array(
    'one' => Array(
        'two' => 3,
    )
);
$merger = Array($array2, $array1);

$results = overlapArrays($merger);

results =

Array(
    'one' => Array(
        'two' => 3,
        'three' => 3
    )
);

合并数组中索引最高的数组具有最低优先级。合并数组中索引最低的数组具有最高优先级。如果您有足够的问题，请告诉我。我正在努力确保我解释得很好。

数组与多维数组合并

3 个答案: