C ++:无法在ostream&内部创建节点指针运算符<<

时间:2014-09-28 02:43:36

标签: c++

我正在使用C ++来实现LinkedList,其他函数和运算符我可以创建Node *就好了。但是当我到达这个运算符“ostream& operator<<(ostream& out,const LinkedList& list)”(输出列表)时,我无法在运算符内部创建临时运算符,可以有谁告诉我导致错误的原因以及如何解决?

这是我的LinkedList.h

#ifndef LINKEDLIST_H
#define LINKEDLIST_H

#include <iostream>

using namespace std;

class LinkedList {
    typedef struct Node{
        int data;
        Node* next;

    bool operator < (const Node& node) const {
        return this->data < node.data;
    }

    bool operator <= (const Node& node) const {
        return this->data <= node.data;
    }

    bool operator > (const Node& node) const {
        return this->data > node.data;
    }

    bool operator >= (const Node& node) const {
        return this->data >= node.data;
     }

    friend ostream& operator << (ostream& out, const LinkedList& list);
    friend istream& operator >> (istream& in, const LinkedList& list);

    } * nodePtr;

public: 
    nodePtr head;
    nodePtr curr;
    LinkedList();

   // functions
    void push_front(int);
    void push_back(int);
    int pop_front();
    int pop_back();
    int size();
    bool contains(int);
    void print();
    void clear();

   // overload
    LinkedList& operator =(const LinkedList& list);
    bool operator !=(const LinkedList& list) const;
    LinkedList operator +(const int v) const;
    LinkedList operator +(const LinkedList& list) const;
    LinkedList operator - (const int v) const;   
    friend ostream& operator << (ostream& out, const LinkedList& list);
    friend istream& operator >> (istream& in, const LinkedList& list);  
   };

 #endif /* LINKEDLIST_H */
在我的LinkedList.cpp中:

ostream& operator << (ostream& out, const LinkedList& list) {
    nodePtr temp = list.head;          <----------------- **Unable to resolve identifier nodePtr**
}

我可以在我的其他功能上创建Node *(nodePtr)。

1 个答案:

答案 0 :(得分:2)

nodePtrLinkedList内定义,需要合格。改变

nodePtr temp = list.head;

LinkedList::nodePtr temp = list.head;
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