Question

我希望这个程序能够从命令行读取指令。它是八进制的数字转换器 - ＆gt;二进制和二进制 - ＆gt;八进制。我不能在运行转换之前告诉它吗？例如./conv八进制二进制11将产生八进制3.我以前运行过linux程序./script输入输出。

#include <stdio.h>
#include <math.h>
int binary_octal(int n);
int octal_binary(int n);
int main()
{
    int n;
    char c;
    printf("Instructions:\n");
    printf("Enter alphabet 'o' to convert binary to octal.\n");
    printf("2. Enter alphabet 'b' to convert octal to binary.\n");
    scanf("%c",&c);
    if ( c=='o' || c=='O')
    {
        printf("Enter a binary number: ");
        scanf("%d",&n);
        printf("%d in binary = %d in octal", n, binary_octal(n));
    }
    if ( c=='b' || c=='B')
    {
        printf("Enter a octal number: ");
        scanf("%d",&n);
        printf("%d in octal = %d in binary",n, octal_binary(n));
    }
    return 0;
}
int binary_octal(int n)  /* Function to convert binary to octal. */
{
    int octal=0, decimal=0, i=0;
    while(n!=0)
    {
        decimal+=(n%10)*pow(2,i);
        ++i;
        n/=10;
    }

/*At this point, the decimal variable contains corresponding decimal value of binary number. */

    i=1;
    while (decimal!=0)
    {
        octal+=(decimal%8)*i;
        decimal/=8;
        i*=10;
    }
    return octal;
}
int octal_binary(int n)  /* Function to convert octal to binary.*/
{
    int decimal=0, binary=0, i=0;
    while (n!=0)
    {
        decimal+=(n%10)*pow(8,i);
        ++i;
        n/=10;
    }
/* At this point, the decimal variable contains corresponding decimal value of that octal number. */
    i=1;
    while(decimal!=0)
    {
        binary+=(decimal%2)*i;
        decimal/=2;
        i*=10;
    }
    return binary;
}

Answer 1

命令行选项通过main和argc传递给argv。

int main(int argc, char** argv)
{
    for(int i=0; i<argc; ++i)
    {
        printf("Option %d is %s\n", i, argv[i]);
    }
}

尝试使用各种命令行参数运行这个迷你程序，你会很快发现它！

C程序从命令行读取输入

1 个答案: