如何在Swift中解析Alamofire API的JSON响应?

时间:2014-09-30 07:12:13

标签: ios json swift alamofire

我编写了以下代码,我在JSON中也得到了响应,但JSON的类型是“AnyObject”,我无法将其转换为Array,以便我可以使用它。

Alamofire.request(.POST, "MY URL", parameters:parameters, encoding: .JSON) .responseJSON
{
    (request, response, JSON, error) in

    println(JSON?)
}

14 个答案:

答案 0 :(得分:147)

Swift 2.0 Alamofire 3.0的答案应该看起来更像是这样:

Alamofire.request(.POST, url, parameters: parameters, encoding:.JSON).responseJSON
{ response in switch response.result {
                case .Success(let JSON):
                    print("Success with JSON: \(JSON)")

                    let response = JSON as! NSDictionary

                    //example if there is an id
                    let userId = response.objectForKey("id")!

                case .Failure(let error):
                    print("Request failed with error: \(error)")
                }
    }

https://github.com/Alamofire/Alamofire/blob/master/Documentation/Alamofire%203.0%20Migration%20Guide.md

Alamofire 4.0和Swift 3.0的更新:

Alamofire.request(url, method: .post, parameters: parameters, encoding: JSONEncoding.default)
            .responseJSON { response in
                print(response)
//to get status code
                if let status = response.response?.statusCode {
                    switch(status){
                    case 201:
                        print("example success")
                    default:
                        print("error with response status: \(status)")
                    }
                }
//to get JSON return value
            if let result = response.result.value {
                let JSON = result as! NSDictionary
                print(JSON)
            }

        }

答案 1 :(得分:27)

如上所述,您可以使用SwiftyJSON库并获取您的值,就像我在下面所做的那样

Alamofire.request(.POST, "MY URL", parameters:parameters, encoding: .JSON) .responseJSON
{
    (request, response, data, error) in

var json = JSON(data: data!)

       println(json)   
       println(json["productList"][1])                 

}

我的json产品列表从脚本返回

{ "productList" :[

{"productName" : "PIZZA","id" : "1","productRate" : "120.00","productDescription" : "PIZZA AT 120Rs","productImage" : "uploads\/pizza.jpeg"},

{"productName" : "BURGER","id" : "2","productRate" : "100.00","productDescription" : "BURGER AT Rs 100","productImage" : "uploads/Burgers.jpg"}    
  ]
}

输出:

{
  "productName" : "BURGER",
  "id" : "2",
  "productRate" : "100.00",
  "productDescription" : "BURGER AT Rs 100",
  "productImage" : "uploads/Burgers.jpg"
}

答案 2 :(得分:23)

我在GitHub上找到 Swift2

的答案

https://github.com/Alamofire/Alamofire/issues/641

Alamofire.request(.GET, URLString, parameters: ["foo": "bar"])
    .responseJSON { request, response, result in
        switch result {
        case .Success(let JSON):
            print("Success with JSON: \(JSON)")

        case .Failure(let data, let error):
            print("Request failed with error: \(error)")

            if let data = data {
                print("Response data: \(NSString(data: data, encoding: NSUTF8StringEncoding)!)")
            }
        }
    }

答案 3 :(得分:19)

Swift 3,Alamofire 4.4和SwiftyJSON:

Alamofire.request(url, method: .get)
  .responseJSON { response in
      if response.data != nil {
        let json = JSON(data: response.data!)
        let name = json["people"][0]["name"].string
        if name != nil {
          print(name!)
        }
      }
  }

这将解析此JSON输入:

{
  people: [
    { name: 'John' },
    { name: 'Dave' }
  ]
}

答案 4 :(得分:17)

我既不是JSON专家,也不是Swift专家,但以下内容对我有用。 :)我从我当前的应用程序中提取了代码,并且只更改了“MyLog to println”,并使用空格缩进以使其显示为代码块(希望我没有破坏它)。

func getServerCourseVersion(){

    Alamofire.request(.GET,"\(PUBLIC_URL)/vtcver.php")
        .responseJSON { (_,_, JSON, _) in
          if let jsonResult = JSON as? Array<Dictionary<String,String>> {
            let courseName = jsonResult[0]["courseName"]
            let courseVersion = jsonResult[0]["courseVersion"]
            let courseZipFile = jsonResult[0]["courseZipFile"]

            println("JSON:    courseName: \(courseName)")
            println("JSON: courseVersion: \(courseVersion)")
            println("JSON: courseZipFile: \(courseZipFile)")

          }
      }
}

希望这有帮助。

编辑:

供参考,这是我的PHP脚本返回的内容:

[{"courseName": "Training Title","courseVersion": "1.01","courseZipFile": "101/files.zip"}]

答案 5 :(得分:9)

swift 3

pod 'Alamofire', '~> 4.4'
pod 'SwiftyJSON'

File json format:
{
    "codeAd": {
        "dateExpire": "2017/12/11",
        "codeRemoveAd":"1231243134"
        }
}

import Alamofire
import SwiftyJSON
    private func downloadJson() {
        Alamofire.request("https://yourlinkdownloadjson/abc").responseJSON { response in
            debugPrint(response)

            if let json = response.data {
                let data = JSON(data: json)
                print("data\(data["codeAd"]["dateExpire"])")
                print("data\(data["codeAd"]["codeRemoveAd"])")
            }
        }
    }

答案 6 :(得分:7)

雨燕5

class User: Decodable {

    var name: String
    var email: String
    var token: String

    enum CodingKeys: String, CodingKey {
        case name
        case email
        case token
    }

    public required init(from decoder: Decoder) throws {
        let container = try decoder.container(keyedBy: CodingKeys.self)
        self.name = try container.decode(String.self, forKey: .name)
        self.email = try container.decode(String.self, forKey: .email)
        self.token = try container.decode(String.self, forKey: .token)
    }
}

Alamofire API

    Alamofire.request("url.endpoint/path", method: .get, parameters: params, encoding: URLEncoding.queryString, headers: nil)
     .validate()
     .responseJSON { response in

        switch (response.result) {

            case .success( _):

            do {
                let users = try JSONDecoder().decode([User].self, from: response.data!)
                print(users)

            } catch let error as NSError {
                print("Failed to load: \(error.localizedDescription)")
            }

             case .failure(let error):
                print("Request error: \(error.localizedDescription)")
         }

答案 7 :(得分:2)

我通常使用Gloss库在iOS中序列化或反序列化JSON。例如,我的JSON看起来像这样:

{"ABDC":[{"AB":"qwerty","CD":"uiop"}],[{"AB":"12334","CD":"asdf"}]}

首先,我在Gloss struct中编写JSON数组:

Struct Struct_Name: Decodable {
   let IJ: String?
   let KL: String?
   init?(json: JSON){
       self.IJ = "AB" <~~ json
       self.KL = "CD" <~~ json
   }
}

然后在Alamofire responseJSON中,我执行以下操作:

Alamofire.request(url, method: .get, paramters: parametersURL).validate(contentType: ["application/json"]).responseJSON{ response in
 switch response.result{
   case .success (let data):
    guard let value = data as? JSON,
       let eventsArrayJSON = value["ABDC"] as? [JSON]
    else { fatalError() }
    let struct_name = [Struct_Name].from(jsonArray: eventsArrayJSON)//the JSON deserialization is done here, after this line you can do anything with your JSON
    for i in 0 ..< Int((struct_name?.count)!) {
       print((struct_name?[i].IJ!)!)
       print((struct_name?[i].KL!)!)
    }
    break

   case .failure(let error):
    print("Error: \(error)")
    break
 }
}

上述代码的输出:

qwerty
uiop
1234
asdf

答案 8 :(得分:1)

我找到了一种方法将response.result.value(在Alamofire responseJSON闭包内)转换为我在我的应用中使用的JSON格式。

我正在使用Alamofire 3和Swift 2.2。

这是我使用的代码:

    Alamofire.request(.POST, requestString,
                      parameters: parameters,
                      encoding: .JSON,
                      headers: headers).validate(statusCode: 200..<303)
                                       .validate(contentType: ["application/json"])
                                       .responseJSON { (response) in
        NSLog("response = \(response)")

        switch response.result {
        case .Success:
            guard let resultValue = response.result.value else {
                NSLog("Result value in response is nil")
                completionHandler(response: nil)
                return
            }

            let responseJSON = JSON(resultValue)

            // I do any processing this function needs to do with the JSON here

            // Here I call a completionHandler I wrote for the success case
        break
        case .Failure(let error):
            NSLog("Error result: \(error)")
            // Here I call a completionHandler I wrote for the failure case
            return
        }

答案 9 :(得分:0)

这是使用Xcode 10.1和Swift 4构建的

完美的组合“ Alamofire”(4.8.1)和“ SwiftyJSON”(4.2.0)。首先,您应该同时安装两个Pod

  

pod 'Alamofire'pod 'SwiftyJSON'

JSON格式的服务器响应:

{
  "args": {}, 
  "headers": {
    "Accept": "*/*", 
    "Accept-Encoding": "gzip;q=1.0, compress;q=0.5", 
    "Accept-Language": "en;q=1.0", 
    "Host": "httpbin.org", 
    "User-Agent": "AlamoFire TEST/1.0 (com.ighost.AlamoFire-TEST; build:1; iOS 12.1.0) Alamofire/4.8.1"
  }, 
  "origin": "200.55.140.181, 200.55.140.181", 
  "url": "https://httpbin.org/get"
}

在这种情况下,我要打印“主机”信息:“主机”:“ httpbin.org”

Alamofire.request("https://httpbin.org/get").validate().responseJSON { response in
        switch response.result {
        case .success:
            print("Validation Successful)")

            if let json = response.data {
                do{
                    let data = try JSON(data: json)
                    let str = data["headers"]["Host"]
                    print("DATA PARSED: \(str)")
                }
                catch{
                print("JSON Error")
                }

            }
        case .failure(let error):
            print(error)
        }
    }

保持冷静和快乐的代码

答案 10 :(得分:0)

在Swift 5中,我们喜欢使用typealias作为补全。 Typlealias只是清理代码而已。

typealias response = (Bool,Any?)->()


static func postCall(_ url : String, param : [String : Any],completion : @escaping response){
    Alamofire.request(url, method: .post, parameters: param, encoding: JSONEncoding.default, headers: [:]).responseJSON { (response) in

        switch response.result {
           case .success(let JSON):
               print("\n\n Success value and JSON: \(JSON)")

           case .failure(let error):
               print("\n\n Request failed with error: \(error)")

           }
    }
}

答案 11 :(得分:0)

简单的答案是让 AlamoFire 直接进行解码。

令人惊讶的是,您没有使用 .responseJSON,因为它返回一个无类型的 json 对象

相反,您使对象可解码 - 并要求 AF 直接解码它们

我的 json 响应包含一组 Account 对象。我只关心 id 和 name 键(虽然还有更多)

struct Account:Codable {
    let id:Int
    let name:String
}

然后简单

    AF.request(url,
               method: .get)
        .responseDecodable(of:[Account].self) { response in
            switch response.result {
            case .success:
                switch response.response?.statusCode {
                case 200:
                    //response.value is of type [Account]
                default:
                    //handle other cases
                }
            case let .failure(error):
                //probably the decoding failed because your json doesn't match the expected format
            }
        }

答案 12 :(得分:-2)

let semaphore = DispatchSemaphore (value: 0)

        var request = URLRequest(url: URL(string: Constant.localBaseurl2 + "compID")!,timeoutInterval: Double.infinity)
                            request.httpMethod = "GET"
                            let task = URLSession.shared.dataTask(with: request) { data, response, error in
                                if let response = response {
                                let nsHTTPResponse = response as! HTTPURLResponse
                                print(nsHTTPResponse)
                                          
                                }
                                if let error = error {
                                print ("\(error)")
                                    return
                                 }
                                
                                if let data = data {
                                    DispatchQueue.main.async {
                                        
                                        let decoder = JSONDecoder()
                                        decoder.keyDecodingStrategy = .convertFromSnakeCase//or any other Decoder\
                                        
                                        do{
                                            
                                            let jsonDecoder = JSONDecoder()
                                            let memberRecord = try jsonDecoder.decode(COMPLAINTSVC.GetComplaints.self, from: data)
                                            print(memberRecord.message)
                                         
                                            for detailData in memberRecord.message{
                                                print(detailData)
                                                
                                                
                                                
                                                
                                            
                                            }
                                            
                                            
                                            
                                        }catch{
                                            
                                            print(error.localizedDescription)
                                        }
                                        
                                      
                                        
                                    }
                             
                                }
                              
                              semaphore.signal()
                            }

                            task.resume()
                            semaphore.wait()

}

答案 13 :(得分:-10)

[R S] = meshgrid(-5:0.1:5, -5:0.1:5);

figure
contour(R, S, R.^2 + S.^2, 5);
axis([-5,5,-5,5])
axis square
hold on

for i=1:50
    a = 0;
    b = 1:2
    B = repmat(b,5,1)
    A = unifrnd(a,B)
    x = A(1:5,1);
    y = A(1:5,2);

    scatter(x,y,'fill')
    hold off
    pause(0.5)
end
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