Question

我有这个数组：

params[:types] = [type1, type2, type3...]

我想使用上面的数组以下列方式填充我的哈希：

params[:hash] = { 
               "type1" => {
                   something: something
               },
               "type2" => {
                    something: something
               },
           }

使用像for这样的for index in i ...params[:types]循环只需使用数组中的最后一个值填充哈希值。

Answer 1

您可以使用each_with_object方法执行此操作：

params = {}
params[:types] = ["type1", "type2", "type3"]
params[:types].each_with_object({}) { |k, h| h[k] = { "something" => "something" } }

最后一行将返回：

=> {"type1"=>{"something"=>"something"}, "type2"=>{"something"=>"something"}, "type3"=>{"something"=>"something"}}

Answer 2

这是一个代码片段示例，可以满足您的需求。

hash = {}
array.each do |a|                                                
  hash[a.to_s] = { "something" => "something" }                  
end

输出：

hash                                                             
=> {
  "type1" => {
    "something" => "something"
  },
  "type2" => {
    "something" => "something"
  },
  "type3" => {
    "something" => "something"
  }
}

Answer 3

你可以这样做：

params = { types: ["type1", "type2", "type3"] }

Hash[params[:types].product([{"something" => "something"}])]
  #=> {"type1"=>{"something"=>"something"},
  #    "type2"=>{"something"=>"something"},
  #    "type3"=>{"something"=>"something"}}

或使用Ruby 2.1，

params[:types].product([{"something" => "something"}]).to_h

如果您想为params[:types]的每个元素添加不同的哈希：

hashes = [{ "something1"=>"something1" }, { "something2"=>"something2" },
          { "something3"=>"something3" }]

然后

Hash[params[:types].zip(hashes)]
  #=> {"type1"=>{"something1"=>"something1"},
  #    "type2"=>{"something2"=>"something2"},
  #    "type3"=>{"something3"=>"something3"}}

填充数组中的哈希

3 个答案: