Question

这就是我所拥有的：

Scanner input = new Scanner(System.in);
    System.out.print("Enter a year: ");
    int Year = input.nextInt();
    System.out.print("Enter a month (first three letters with the first"
            + " letter uppercase): ");
    String Month = input.next();

    String ThirtyOne = "Jan" + "Mar" + "May" + "Jul" + "Aug" + "Oct" + "Dec";
    String DaysThirtyOne = ThirtyOne.substring(21) + "31";

    String Thirty = "Apr" + "Jun" + "Sep" + "Nov";
    String DaysThirty = Thirty.substring(12) + "30";

    String TwentyEight = "Feb";
    String DaysTwentyEight = TwentyEight.substring(3) + "28";
    String DaysLeapYear = TwentyEight.substring(3) + "29";


    boolean isLeapYear = ((Year % 4 == 0) && (Year % 100 != 0) && (Year % 400 == 0));

    if (ThirtyOne.contains(Month)) {
        System.out.println(Month + " " + Year + " has " + DaysThirtyOne 
                + " days in it.");
    }
    if (Thirty.contains(Month)) {
        System.out.println(Month + " " + Year + " has " + DaysThirty 
                + " days in it.");
    }
    if(TwentyEight.contains(Month)) {
        System.out.println(Month + " " + Year + " has " + DaysTwentyEight 
                + " days in it.");
    }
    if (isLeapYear) {
        System.out.println(Month + " " + Year + " has " + DaysLeapYear 
                + " days in it.");
    }

我是编程新手，所以如果这段代码看起来不成熟，我也不会感到惊讶。无论如何，我有一年和一个月的用户输入（前三个字母）。我为闰年创建了一个布尔变量，表示用户输入的任何年份需要被4,100和400整除。然后，我创建了一个if语句，如果它是打印出来的闰年“2月（无论哪一年）用户输入）中有DaysLeapYear。“我认为我的算法有问题，因为如果我要取出TwentyEight的if语句并且只保留闰年if语句，那么计算机甚至不会打印出2月份如果是闰年那么多天。再一次，我认为我在算法中出错了，但它可能在其他地方，我希望再看看这个，看看有人看到的东西我不是因为我毕竟是新手。

Answer 1

首先你的isLeapYear条件需要改变。

boolean isLeapYear = ((Year % 4 == 0) && (Year % 100 != 0) || (Year % 400 == 0));

接下来你的if（TwentyEight.contains（月））需要改变以考虑闰年。

if(TwentyEight.contains(Month) && !isLeapYear) {
        System.out.println(Month + " " + Year + " has " + DaysTwentyEight
                + " days in it.");
}

为什么我的闰年算法不起作用（Java）？

1 个答案: