将String转换为int - java.lang.NumberFormatException.forInputString

时间:2014-10-03 21:42:40

标签: java string parseint

为什么这不起作用并抛出以下错误?

System.out.println(Integer.parseInt("A5"));

错误是:

 at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
        at java.lang.Integer.parseInt(Integer.java:492)
        at java.lang.Integer.parseInt(Integer.java:527)
        at DecisionTreeImpl.createTree(DecisionTreeImpl.java:321)
        at DecisionTreeImpl.<init>(DecisionTreeImpl.java:59)

此外,如果这不是将“A5”这样的字符串转换为整数的好方法,那么在Java中正确执行它的方法是什么?

我获得了一个课程(我根本不应该修改它),如下所示:

public class DecTreeNode {
    Integer label; //for 
    Integer attribute;
    Integer parentAttributeValue; // if is the root, set to "-1"
    boolean terminal;
    List<DecTreeNode> children;

所以当我实例化这个类时,我需要传递给它的所有值(包括属性和标签都是字符串)所以我不知道我现在应该做什么,因为Integer.ParseInt让我失望了!

作为提示您可能希望从DecTreeNode类继承,但我不确定它是否相关!知道如何解决这个问题吗?

root= new DecTreeNode((trainingSet.labels.get(getMajority(instances, trainingSet.labels.size())),trainingSet.attributes.get(biggestEntropy), -1, TRUE);

这是我收到的错误:

The constructor DecTreeNode(String, String, int, boolean) is undefined

然而问题是我不允许修改类DecTreeNode以获得新的构造函数。

以下是不应修改的完整DecTreeNode:

/**
 * Possible class for internal organization of a decision tree.
 * Included to show standardized output method, print().
 * 
 * Do not modify. If you use,
 * create child class DecTreeNodeImpl that inherits the methods.
 * 
 */
public class DecTreeNode {
    Integer label; //for 
    Integer attribute;
    Integer parentAttributeValue; // if is the root, set to "-1"
    boolean terminal;
    List<DecTreeNode> children;

    DecTreeNode(Integer _label, Integer _attribute, Integer _parentAttributeValue, boolean _terminal) {
        label = _label;
        attribute = _attribute;
        parentAttributeValue = _parentAttributeValue;
        terminal = _terminal;
        if (_terminal) {
            children = null;
        } else {
            children = new ArrayList<DecTreeNode>();
        }
    }

    /**
     * Add child to the node.
     * 
     * For printing to be consistent, children should be added
     * in order of the attribute values as specified in the
     * dataset.
     */
    public void addChild(DecTreeNode child) {
        if (children != null) {
            children.add(child);
        }
    }
}

这是TrainingSet类:

public class DataSet {
    public List<String> labels = null;          // ordered list of class labels
    public List<String> attributes = null;      // ordered list of attributes
    public Map<String, List<String> > attributeValues = null; // map to ordered discrete values taken by attributes 
    public List<Instance> instances = null; // ordered list of instances
    private final String DELIMITER = ",";   // Used to split input strings

3 个答案:

答案 0 :(得分:1)

它告诉你&#34;构造函数DecTreeNode(String,String,int,boolean)是未定义的&#34;因为您的类DecTreeNode没有定义具有这些数据类型的构造函数。您可以创建一个扩展DecTreeNode的类DecTreeNodeImpl(如DecTreeNode类中的注释所示)并实现需要String类型参数的所有方法/构造函数。

答案 1 :(得分:0)

如果label始终是一个char,那么解决方案很简单:

System.out.println(Integer.parseInt("A5".substring(1)));

答案 2 :(得分:0)

由于我们不知道有多少个字母(1个或更多),我个人会这样做,删除所有非数字:

String labeledNumber="A5"

String str = labeledNumber.replaceAll("\\D+","");

System.out.println(Integer.parseInt(str));

这也适用于以下标签:“abc12”“a-1232”等。