Question

我有以下createcommand：

$query = Yii::app()->db->createCommand()
    ->select('q.*, qcia.value, qcim.value')
    ->from('quotas q')
    ->leftjoin('quota_company_item_activations qcia', 'qcia.quota_id = q.id')
    ->leftjoin('quota_company_item_mrcs qcim', 'qcim.quota_id = q.id')
    ->where('q.id=:id', array(':id' => $quota_id))
    ->queryRow();

在结果数组中，我应该有两倍的值字段，但数组看起来像这样：

[id] => 3
[name] => September Sales Quotas
[company_id] => 1
[user_id] => 22
[datestart] => 2014-09-01
[dateend] => 2014-09-30
[created] => 2014-09-30 21:12:44
[modified] => 0000-00-00 00:00:00
[value] => 60.00

为什么它只检索一个值（来自最后一个左连接）？

Answer 1

你需要为其中一个值使用别名.. php数组由键索引..第一个值被第二个值覆盖用这样的东西

$query = Yii::app()->db->createCommand()
    ->select('q.*, qcia.value avalue, qcim.value mvalue') 
    ->from('quotas q')
    ->leftjoin('quota_company_item_activations qcia', 'qcia.quota_id = q.id')
    ->leftjoin('quota_company_item_mrcs qcim', 'qcim.quota_id = q.id')
    ->where('q.id=:id', array(':id' => $quota_id))
    ->queryRow();

Answer 2

尝试使用别名，这样您就可以获得不同的value列。

$query = Yii::app()->db->createCommand()
->select('q.*, qcia.value AS qcia_value, qcim.value AS qcim_value')
->from('quotas q')
->leftjoin('quota_company_item_activations qcia', 'qcia.quota_id = q.id')
->leftjoin('quota_company_item_mrcs qcim', 'qcim.quota_id = q.id')
->where('q.id=:id', array(':id' => $quota_id))
->queryRow();

var_dump($query);

yii多个连接不显示所有列

2 个答案: