Question

所以我正在针对这个rspec运行我的方法，一切都过去了。但我无法帮助，但我认为时间安排应该抛弃它，是否有一些我不知道为什么不存在的东西？即使该方法通过，rspec中的信息如何适用于该方法？

这是我的方法：

def measure(num=1, &block)

n=0
arr = []
while n <= num-1
    a=Time.now
    block.call
    b=Time.now
    arr << (b-a)
    n += 1
end
sum = arr.inject(:+)
    avgtime = sum/num
end

这是我的rspec文件的一部分：

@eleven_am = Time.parse("2011-1-2 11:00:00")
it "takes exactly 1 second to run a block that sleeps for 1 second (with stubs)" do
  fake_time = @eleven_am
  Time.stub(:now) { fake_time }
  elapsed_time = measure do
    fake_time += 60  # adds one minute to fake_time
  end
  elapsed_time.should == 60
end

it "returns the average time, not the total time, when running multiple times" do
  run_times = [8,6,5,7]
  fake_time = @eleven_am
  Time.stub(:now) { fake_time }
  average_time = measure(4) do
    fake_time += run_times.pop
  end
  average_time.should == 6.5
end

RSPEC通过方法，但我错过了这一点？

0 个答案: