Question

当我在此代码中回显结果时，为什么我没有得到任何东西：

$result1 = '<HTML><HEAD><TITLE>Moved Temporarily</TITLE></HEAD><BODY BGCOLOR="#FFFFFF" TEXT="#000000"><H1>Moved Temporarily</H1>The document has moved <A HREF="https://accounts.google.com/ServiceLogin?service=lso&amp;">here</A>.</BODY></HTML>';
$dom = new DOMDocument;
$dom->loadHTML($result1);
$items = $dom->getElementsByTagName('HEAD');
echo $items->item(0); // error

Answer 1

您必须使用小写标记名称：

$result1 = '<HTML><HEAD><TITLE>Moved Temporarily</TITLE></HEAD><BODY BGCOLOR="#FFFFFF" TEXT="#000000"><H1>Moved Temporarily</H1>The document has moved <A HREF="https://accounts.google.com/ServiceLogin?service=lso&amp;">here</A>.</BODY></HTML>';
$dom = new DOMDocument;
$dom->loadHTML($result1);
$items = $dom->getElementsByTagName('head');
                                     ^^^

旁注：始终打开错误报告以获取有用信息：

error_reporting(E_ALL);
ini_set('display_errors', '1');

你不能直接回应，因为这会返回DOM类。

循环过头儿童：

echo '<pre>';
foreach($items->item(0)->childNodes as $child) {
    print_r($child); // most likely this will show you the child `<title>` node
}

DOMElement getElementsByTagName（）不起作用

1 个答案: