Question

如何在main中调用convertName方法？当我尝试其他方式时，它出现了错误不能从静态区域引用非静态方法。

/*
This program will take a name string consisting of EITHER a first name followed by a last name 
(nonstandard format) or a last name followed by a comma then a first name (standard format). 
Ie. “Joe Smith” vs. “Smith, Joe”. This program will convert the string to standard format if 
it is not already in standard format.
*/
package name;

public class Name {

    public static void main(String[] Args){
            boolean flag1 = hasComma ("Alex Caramagno");

    }
    public static boolean hasComma(String name) {
            // indexOf will return -1 if a comma is not found
            return name.indexOf(',') >= 0; 
    }

    public String convertName(String name) {
            if (hasComma(name)) {
                    return name;
            }

            int index = name.indexOf(' ');
            String first = name.substring(0, index);
            String last = name.substring(index+1);
            String convertedName = last + ", " + first;
            return convertedName;   
    }

    }

Answer 1

由于该方法不是static，因此您需要Name的实例。

String str = "some string";
new Name().convertName(str);

或者，改变

public String convertName(String name) {

到

public static String convertName(String name) {

然后在main()

String str = "some string";
convertName(str); // <-- calling a static method doesn't need an instance.

如何从main调用方法

1 个答案: