每日总和,月初至今,MTD平均值,上个月平均值

时间:2014-10-16 01:42:18

标签: sql sql-server group-by sum average

请帮助我解决与SUM,AVG,MTD SUM相关的问题,关于通过设施中的仪表查找油量流量。

说,有两个设施

  1. NORTH - 有米N1,N2
  2. SOUTH - 有米S1,S2
  3. 每天都有流量计。表FACILITY_OIL如下所示 -

    TimeStamp----------Facility----------Meter----------OilVolume
    
    10-SEP-2014    |   NORTH        |    N1       |     100
    
    10-SEP-2014    |   NORTH        |    N2       |     200
    
    10-SEP-2014    |   SOUTH        |    S1       |     300
    
    10-SEP-2014    |   SOUTH        |    S2       |     400
    
    
    10-OCT-2014    |   NORTH        |    N1       |     100
    
    10-OCT-2014    |   NORTH        |    N2       |     200
    
    10-OCT-2014    |   SOUTH        |    S1       |     300
    
    10-OCT-2014    |   SOUTH        |    S2       |     400
    
    11-OCT-2014    |   NORTH        |    N1       |     400
    
    11-OCT-2014    |   NORTH        |    N2       |     300
    
    11-OCT-2014    |   SOUTH        |    S1       |     200
    
    11-OCT-2014    |   SOUTH        |    S2       |     100
    
    12-OCT-2014    |   NORTH        |    N1       |     100
    
    12-OCT-2014    |   NORTH        |    N2       |     200
    
    12-OCT-2014    |   SOUTH        |    S1       |     300
    
    12-OCT-2014    |   SOUTH        |    S2       |     400
    

    我必须找到按设施分组的以下内容:

    1. 某一天设施中所有仪表的油量总和。
    2. 油量通过米的月初至今。
    3. MTD油量的平均值
    4. 上个月的油量平均值
    5. 输出应如下所示12-OCT

      Facility-----DailySum-----MTD_Sum-----MTD_Avg-----Prev_Month_Avg
      
      NORTH    |   300     |    1300    |   108.33   |  10
      
      SOUTH    |   700     |    1700    |   141.66   |  23.33
      
      Here for NORTH on 12-OCT,
      
      DailySum = (N1+N2)
      
      MTD SUM = (N1 + N2) from 01-Oct to 12-Oct
      
      MTD_Avg = MTD_SUM/12days
      
      Pre_Month_Avg = (100+200)/30
      

      是否可以以相同的格式输出。我的局限是我不能使用SP。它必须是一种观点。

      我尝试使用group by但无法实现它。任何帮助深表感谢。万分感谢!


      感谢您的帮助!

      似乎有一天工作完美。我能够使用您的查询。

      我添加了#rol;'在最后获得总和。但是,现在需求已更改为获取当天每天的数据集。所以看起来应该如下:

      Timestamp--Facility--DailySum--MTD_Sum--MTD_Avg--Prev_Month_Avg
      10-Oct | NORTH | 300 | 1300 | 108.33 | 10
      10-Oct | SOUTH | 700 | 1700 | 141.66 | 23.33
      10-Oct | TOTAL | 1000| 3000 | 249.99 | 33.33
      
      12-Oct | NORTH | 300 | 1300 | 108.33 | 10
      12-Oct | SOUTH | 700 | 1700 | 141.66 | 23.33
      12-Oct | TOTAL | 1000| 3000 | 249.99 | 33.33
      

      我尝试过你的修改过的查询 -

      select case when null then 'TOTAL' else Facility end as 'Facility'
      ,sum(case when [TimeStamp]>=dateadd(dd,datediff(dd,0,getdate()),0) then OilVolume else 0 end) as DailySum
      ,sum(case when [TimeStamp]>=dateadd(mm,datediff(mm,0,getdate()),0) then OilVolume else 0 end) as MTD_Sum
      ,sum(case when [TimeStamp]>=dateadd(mm,datediff(mm,0,getdate()),0) then OilVolume else 0 end)/datepart(dd,getdate()) as MTD_Avg
      ,sum(case when [TimeStamp]>=dateadd(mm,datediff(mm,0,getdate()),0) then 0 else OilVolume end)/datepart(dd,dateadd(dd,datepart(dd,getdate())*-1,getdate())) as Prev_Month_Avg
      from yourtable
      where [TimeStamp]>=dateadd(mm,datediff(mm,0,getdate())-1,0)
      group by Timestamp, Facility with rollup
      

      它似乎不适用于简单的分组。我不知道如何获得一天的重复结果。我不能使用CURSOR或循环视图。请帮忙。谢谢!

1 个答案:

答案 0 :(得分:0)

我会使用案例

select
sum(case when timestamp = '12-OCT-2014' then meter + oilVolume else 0 end),
sum(case when timestamp between '01-OCT-2014' and '12-OCT-2014' then meter + volume else 0 end),
sum(case when timestamp between  '01-OCT-2014' and '12-OCT-2014' then meter + volume else 0 end) / datediff("dd",'01-OCT-2014' , '12-OCT-2014'),
sum(case when timestamp between '01-SEP-2014' and '30-SEP-2014' then meter + volume  else 0 end ) / datediff("dd",'01-SEP-2014' , '30-SEP-2014')
from ...

您可以使用参数更改日期。

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