Question

程序应该读取输入的数字并确定它们是偶数还是奇数。然后它需要显示奇数和偶数，以及输入数字的平均值。它会在输入0时停止。

我的问题是它只是在输入第一个号码后挂起。

#include "stdio.h"
int main(void)
{
    int oddcount = 0, evencount = 0; /* Count of even and odd numbers. */
    int number;
    float avge = 0, avgo = 0;        /* Average for even and odd numbers.  */
    int evennum = 0, oddnum = 0;

    printf("Enter a number or enter 0 to stop: ");
    scanf_s("%i", &number);
    while(number != 0)
    {
        if(number % 2 == 0)
        { evencount = evencount + 1;
            evennum += number; }
        else
        { oddcount = oddcount + 1;
            oddnum += number; }
    }

    if(oddnum != 0)
        avgo = oddnum / oddcount;   /* Finding the odd average.  */

    if(evennum != 0)
        avge = evennum / evencount; /* Finding the even average.  */

    printf("Here is the count odd %i and even %i numbers.\n", oddcount, evencount);
    printf("And their averages %f odd and %f even.\n", avgo, avge);

    return 0;
}

Answer 1

因为它是一个无限循环...

while(number != 0)
{
    if(number % 2 == 0)
    { evencount = evencount + 1;
        evennum += number; }
    else
    { oddcount = oddcount + 1;
        oddnum += number; }
}

在这里，你的while循环引导变量number永远不会在迭代之间被修改，这使得它保持不变，因此，while条件将永久地重新生成...

可能的解决方案 似乎是： -

int number=1;     // just for initialisation with a non-zero number...
while(number != 0)
{
  printf("Enter a number or enter 0 to stop: ");
  scanf_s("%i", &number);
    if(number % 2 == 0)
    { evencount = evencount + 1;
        evennum += number; }
    else
    { oddcount = oddcount + 1;
        oddnum += number; }
}

Answer 2

在第一个之后你没有读新数字。尝试像

这样的东西

while( scanf("%d", &number) == 1 && number != 0){
//Count evens and odds
}

另一种处理此问题的方法是在while循环结束时添加另一个scanf

程序在输入后挂起

2 个答案: