选择列等于另一个查询的任何值的位置

Question

我有一个查询来查找名为entryEntryPairs的表中的关系：

if (!$result = $mysqli->query(
    "SELECT entryIdA AS relatedId FROM entryEntryPairs WHERE entryIdB = ".$inRow["id"].
    " UNION ".
    "SELECT entryIdB AS relatedId FROM entryEntryPairs WHERE entryIdA = ".$inRow["id"]
)) return "Something went wrong";

但是，我真正想要的是将所有relatedId用作对名为entry的表的更大查询的一部分。形式的东西：

SELECT title FROM entry WHERE id =

id =右侧缺失的部分将是relatedIds的全部内容。这可以在一个较大的查询中完成，还是必须迭代relatedId右侧每个id =插入的第一个查询的结果？

Answer 1

您可以尝试使用IN

"SELECT title FROM entry WHERE id IN (SELECT entryIdA AS relatedId FROM entryEntryPairs WHERE entryIdB = ".$inRow["id"].
" UNION ".
"SELECT entryIdB AS relatedId FROM entryEntryPairs WHERE entryIdA = ".$inRow["id"].")"