Question

在UesrDAO类中获取空指针异常，因为sessionFactory对象始终为null。如果这有帮助，我发现如果使用＆＃39; new＆＃39;手动创建DAO，就会发生这种情况。而不是让弹簧处理它。我没有这样做，我在服务类中注入UserDAO但仍然将sessionFactory作为null。

感谢任何帮助，谢谢。

以下是相关文件的内容：

的hibernate.cfg.xml

<?xml version='1.0' encoding='utf-8'?>
<beans xmlns="http://www.springframework.org/schema/beans"
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xsi:schemaLocation="http://www.springframework.org/schema/beans
        http://www.springframework.org/schema/beans/spring-beans-3.1.xsd">

    <bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
        <property name="location">
            <value>/WEB-INF/properties/database.properties</value>
        </property>
    </bean>
    <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
        <property name="driverClassName" value="${jdbc.driverClassName}" />
        <property name="url" value="${jdbc.url}" />
        <property name="username" value="${jdbc.username}" />
        <property name="password" value="${jdbc.password}" />
    </bean>
    <bean id="sessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
        <property name="dataSource">
            <ref bean="dataSource"/>
        </property>
        <property name="hibernateProperties">
            <props>
                <prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop>
                <prop key="hibernate.show_sql">true</prop>
            </props>
        </property>
        <property name="packagesToScan">
            <list>
                <value>org.questionbank.dto</value>
            </list>
        </property>
    </bean>
</beans>

的applicationContext.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
  xmlns:security="http://www.springframework.org/schema/security"
  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xmlns:context="http://www.springframework.org/schema/context"
  xmlns:tx="http://www.springframework.org/schema/tx"
  xmlns:mvc="http://www.springframework.org/schema/mvc"
  xsi:schemaLocation="http://www.springframework.org/schema/beans
  http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
  http://www.springframework.org/schema/security
  http://www.springframework.org/schema/security/spring-security-3.2.xsd
  http://www.springframework.org/schema/context 
  http://www.springframework.org/schema/context/spring-context-3.2.xsd
  http://www.springframework.org/schema/tx 
  http://www.springframework.org/schema/tx/spring-tx.xsd
  http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd">

    <import resource="hibernate.cfg.xml"/>
    <mvc:annotation-driven />
    <tx:annotation-driven />
    <context:annotation-config />
    <!--  To scan the components -->
    <context:component-scan base-package="org.questionbank"/>
    <bean id = "transactionManager" class = "org.springframework.orm.hibernate4.HibernateTransactionManager">
        <property name = "sessionFactory" ref = "sessionFactory" />
    </bean> 
</beans>

DAO课程：

public class UserDAO 
{
    protected static Logger logger = Logger.getLogger("dao");

    @Autowired
    private SessionFactory sessionFactory;

    public UserDTO searchDatabase(String username) 
    {
        logger.debug("Seraching for user in DB");
        UserDTO user=new UserDTO();
        Query query = sessionFactory.getCurrentSession().createQuery("FROM UserDTO u WHERE u.userName = :userName");
        query.setParameter("userName", username);
        user = (UserDTO) query.uniqueResult();
        if(user!=null)
            return user;
        logger.error("User does not exist!");
        throw new RuntimeException("User does not exist!");
    }
}

服务类：

@Transactional(readOnly = true)
public class CustomUserDetailsService implements UserDetailsService 
{
    protected static Logger logger = Logger.getLogger("service");
    @Autowired
    private UserDAO userDAO;
    public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException, DataAccessException 
    {
        UserDetails user = null;
        try 
        {
            UserDTO dbUser = userDAO.searchDatabase(username);
            user =  new User(
                    dbUser.getUserName(), 
                    dbUser.getPassword().toLowerCase(),
                    true,
                    true,
                    true,
                    true,
                    getAuthorities(Integer.parseInt(dbUser.getAccess())));
            } catch (Exception e) {
            logger.error("Error in retrieving user");
            e.printStackTrace();
            throw new UsernameNotFoundException("Error in retrieving user");
        }
        return user;
    }

Answer 1

使用<context:annotation-config />和<context:component-scan base-package="org.questionbank"/>的当前配置启用了功能上的前半部分，以使Spring正确识别并注入您的bean。

另一半实际上是将bean声明为Spring管理的组件。

您可以通过以下两种方式之一完成此操作。使用applicationContext.xml标记在<bean />中声明bean（就像使用transactionManager一样）或使用stereotype annotation（例如@Component，{{ 3}}，@Repository或@Service）。

@Repository
public class UserDAO { // ...

和

@Service
public class CustomUserDetailsService { // ...

自动连接的sessionFactory对象为null

1 个答案: