Question

我存储＆＃34; start_time＆＃34;，＆＃34; finish_time＆＃34;和＆＃34;饭＆＃34;时间

start_time = DATETIME
finish_time = DATETIME
meal = INT - store minitues

现在我想在start_time，finish_time之间得到尊重，之后我想减去用餐时间如何做到这一点，

eg:
start_time             finish_time           meal
2014-10-24 08:30:00    2014-10-24 18:30:00   45

输出应为： 9:15

如何仅使用MySQL，

我尝试使用TIMESTAMPDIFF，但我不知道如何减去膳食并将其转换为H：m格式：

TIMESTAMPDIFF(MINUTE,start_time, finish_time)

Answer 1

做普通的减法：

TIMESTAMPDIFF(MINUTE,start_time, finish_time) - meal

要将其转换为H:m格式，请将其除以60并从60获得模数：

CONCAT(FLOOR((TIMESTAMPDIFF(MINUTE,start_time, finish_time) - meal)/60),
      ':', 
      (TIMESTAMPDIFF(MINUTE,start_time, finish_time) - meal) % 60)

Answer 2

有一种更好的方法：

SEC_TO_TIME(TIMESTAMPDIFF(MINUTE,start_time, finish_time))

Answer 3

SELECT 
    SEC_TO_TIME(
        (
            (
                UNIX_TIMESTAMP(`finish_time`) - UNIX_TIMESTAMP(`start_time`) /* difference in seconds */
            ) / 60 - `meal` /* transform in minutes, substract minutes */
        ) * 60 /* seconds again */
    ) AS `timediff` /* to time :) */
FROM `table`

MySQL如何减去两个DATETIME和INT值

3 个答案: