unix sed只有在整个单词存在时才替换行

Question

我在文字中有三行

clm_id double, actv_clm_id double, clm_id int,

我想将整个单词clm_id所在的行替换为

clm_id bigint, actv_clm_id double, clm_id bigint,

任何指针？

Answer 1

您可以使用此命令：

sed 's/.*\(^\| \)clm_id\( \|$\).*/clm_id bigint/' input.file 

<强>解释

/         Delimiter

.*        Anything (optional)

\(^\| \)  Selects the beginning of the line `^` or `|` a whitespace before the word.
          into a capturing group (Note that `(|)` need to get escaped by a `\'

clm_id    Selects clm_id

\( \|$\)  ... followed by a whitespace or the end of the line `$`

.*        Anything (optional)

/         Delimiter

<强>输出：

clm_id bigint
actv_clm_id double
clm_id bigint

Answer 2

这可能适合你（GNU sed）：

sed '/\<clm_id\>/c\clm_id bigint,' file