按int排序对象数组,然后按字母顺序排序

时间:2014-10-24 03:28:21

标签: javascript arrays sorting

我有一个数组,其中包含有关状态特征的各种信息,需要通过几种方式对其进行修改。首先,如果区域相同,我需要按区域排序,然后按名称排序。所以我使用parseInt获取实际的int而不是字符串,但现在我输了。我如何实现这一目标?我还需要找到填充最多/填充最少的状态并将其存储在变量中。

(function() {
'use strict';

var states = [{
    "name": "Alaska",
    "area": "663,268 sq mi",
    "population": 735132
}, {
    "name": "California",
    "area": "163,696 sq mi",
    "population": 38332521
}, {
    "name": "oregon",
    "area": "98,381 sq mi",
    "population": 3899353
}, {
    "name": "washington",
    "area": "71,300 sq mi",
    "population": 6971406
}];

var moddedStates = {};
for (var i = 0; i < states.length; i++) {
    var area = parseInt(states[i].area);

}
}());

1 个答案:

答案 0 :(得分:0)

我相信这段代码会做你想要的一切。请注意使用replace来说明逗号​​,并使用parseFloat代替parseInt,以防某些尺寸包含小数点右边的数字。 (在比较美国各州的规模时可能不是问题,但仍然是进入的良好习惯......)

(function() {
    'use strict';
    
    var states = [{
        "name": "Alaska",
        "area": "663,268 sq mi",
        "population": 735132
    }, {
        "name": "California",
        "area": "163,696 sq mi",
        "population": 38332521
    }, {
        "name": "oregon",
        "area": "98,381 sq mi",
        "population": 3899353
    }, {
        "name": "washington",
        "area": "71,300 sq mi",
        "population": 6971406
    }];
    
    var mostPopulated = null;
    var leastPopulated = null;

    states.sort(function (a, b) {
        var aArea = parseFloat(a.area.replace(/,/g, ''));
        var bArea = parseFloat(b.area.replace(/,/g, ''));
        if (aArea < bArea) return -1;
        else if (bArea < aArea) return 1;
        else if (a.name < b.name) return -1;
        else if (b.name < a.name) return 1;
        else return 0;
    });
    
    for (var i = 0, len = states.length; i < len; i++) {
        if (!mostPopulated || states[i].population > mostPopulated.population) {
            mostPopulated = states[i];
        }
        if (!leastPopulated || states[i].population < leastPopulated.population) {
            leastPopulated = states[i];
        }
    }
    
    console.log(states);
    console.log(mostPopulated);
    console.log(leastPopulated);
}());

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