我在javascript中创建了一个计时器应用程序。 首先,它将当前的UTC日期带到init计时器并带有一些引用。这是代码
on_timer: function(e) {
var self = this;
if ($(e.target).hasClass("pt_timer_start")) {
var current_date = this.get_current_UTCDate();
this.project_timesheet_db.set_current_timer_activity({date: current_date});
this.start_interval();
this.initialize_timer();
this.$el.find(".pt_timer_start,.pt_timer_stop").toggleClass("o_hidden");
现在,一旦计时器启动,经过一段时间跨度计时器参考上面的on_timer: function(e)
函数已经过了一些时间。
此功能
start_interval: function() {
var timer_activity = this.project_timesheet_db.get_current_timer_activity();
var self = this;
this.intervalTimer = setInterval(function(){
self.$el.find(".pt_duration").each(function() {
var el_hour = $(this).find("span.hours");
var el_minute = $(this).find("span.minutes");
var minute = parseInt(el_minute.text());
if(minute >= 60) {
el_hour.text(_.str.sprintf("%02d", parseInt(el_hour.text()) + 1));
minute = 0;
}
el_minute.text(_.str.sprintf("%02d", minute));
var el_second = $(this).find("span.seconds");
var seconds = parseInt(el_second.text()) + 1;
if(seconds > 60) {
el_minute.text(_.str.sprintf("%02d", parseInt(el_minute.text()) + 1));
seconds = 0;
}
el_second.text(_.str.sprintf("%02d", seconds));
});
}, 1000);
},
现在,考虑 el_hour , el_minute , el_seconds 如何在HH:MM中计算初始时间和当前计时器值之间的时差:SS方式。
提前感谢您的帮助
答案 0 :(得分:7)
要将H:M:S转换为秒,您可以使用简单的函数,如:
// Convert H:M:S to seconds
// Seconds are optional (i.e. n:n is treated as h:s)
function hmsToSeconds(s) {
var b = s.split(':');
return b[0]*3600 + b[1]*60 + (+b[2] || 0);
}
然后将秒转换回HMS:
// Convert seconds to hh:mm:ss
// Allow for -ve time values
function secondsToHMS(secs) {
function z(n){return (n<10?'0':'') + n;}
var sign = secs < 0? '-':'';
secs = Math.abs(secs);
return sign + z(secs/3600 |0) + ':' + z((secs%3600) / 60 |0) + ':' + z(secs%60);
}
var a = '01:43:28';
var b = '12:22:46';
console.log(secondsToHMS(hmsToSeconds(a) - hmsToSeconds(b))); // -10:39:18
console.log(secondsToHMS(hmsToSeconds(b) - hmsToSeconds(a))); // 10:39:18
您可能希望将函数名称缩写为:
toHMS(toSec(a) - toSec(b)); // -10:39:18
请注意,这并未涵盖时间跨越夏令时边界的位置。为此,您需要完全合格的日期,包括年,月和日。使用这些值创建日期对象,查找差异,转换为秒并使用 secondsToHMS 函数。
问题标题提到日期,但内容似乎只提及小时,分钟和秒的字符串。
如果您有Date对象,您可以使用以下命令获取它们之间的差异:
var diffMilliseconds = date0 - date1;
并转换为秒:
var diffSeconds = diffMilliseconds / 1000;
使用上面的 secondsToHMS 函数显示为HH:MM:SS:
secondsToHMS((date0 - date1) / 1000);
e.g。
var d0 = new Date(2014,10,10,1,43,28);
var d1 = new Date(2014,10,10,12,22,46);
console.log( secondsToHMS((d0 - d1) / 1000)); // -10:39:18
答案 1 :(得分:1)
我认为有一个更简单的解决方案。
/// Loads An SCNSphere At The Position Of An ARAnchor
///
/// - Parameter plane: SCNNode
func loadSphereAtAnchorPosition(_ anchor: ARPlaneAnchor) {
let sphereNode = SCNNode()
let sphereNodeGeometry = SCNSphere(radius: 0.01)
sphereNodeGeometry.firstMaterial?.diffuse.contents = UIColor.cyan
sphereNode.geometry = sphereNodeGeometry
sphereNode.position = SCNVector3(anchor.transform.columns.3.x,
anchor.transform.columns.3.y,
anchor.transform.columns.3.z)
augmentedRealityView?.scene.rootNode.addChildNode(sphereNode)
}
&#13;
答案 2 :(得分:1)
这可能是简单的答案
var d1 = new Date(2014,10,11,1,43,28);
var d2 = new Date(2014,10,11,2,53,58);
var date = new Date(d2-d1);
var hour = date.getUTCHours();
var min = date.getUTCMinutes();
var sec = date.getUTCSeconds();
var day = date.getUTCDate() - 1;
console.log(day + ":" + hour + ":" + min + ":" + sec)
答案 3 :(得分:1)
const dateDiffToString = (a, b) => {
let diff = Math.abs(a - b);
let ms = diff % 1000;
diff = (diff - ms) / 1000;
let s = diff % 60;
diff = (diff - s) / 60;
let m = diff % 60;
diff = (diff - m) / 60;
let h = diff;
let ss = s <= 9 && s >= 0 ? `0${s}` : s;
let mm = m <= 9 && m >= 0 ? `0${m}` : m;
let hh = h <= 9 && h >= 0 ? `0${h}` : h;
return hh + ':' + mm + ':' + ss;
};